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In article <5ahng7$9hh@netnews.upenn.edu> rsherman@mail.med.upenn.edu (Richard S. Herman) writes: >Hey... i made a mistake they pyramid should look like > > 1 > 1 1 > 2 1 > 12 11 > 111 221 > >I need the next line of this number pryamid... thanks alot again!! 312211 (three ones, two twos, one one) I think this is in the rec.puzzles FAQ -- dennis@netcom.com (Dennis Yelle) "You must do the thing you think you cannot do." -- Eleanor RooseveltReturn to Top
client@mediom.qc.ca (Nom du client) writes: > > Can someone could explain me clearly why ABC conjecture should be true? See Lang's excellent survey (there is also a 5 page exposition in the 3rd (1993) edition of his Algebra). Lang, Serge. Old and new conjectured Diophantine inequalities. Bull. Amer. Math. Soc. (N.S.) 23 (1990), no. 1, 37--75. MR 90k:11032 (Reviewer: D. J. Lewis) 11D75 (11-02 11D72 11J25) Other useful surveys are Oesterle, Joseph. Nouvelles approches du "theoreme" de Fermat. (French) [New approaches to Fermat's ``theorem''] Seminaire Bourbaki, Vol. 1987/88. Asterisque No. 161-162 (1988), Exp. No. 694, 4, 165--186 (1989). MR 90g:11038 (Reviewer: Toshihiro Hadano) 11D41 (11G05 11N37 14G25) Frey, Gerhard. Links between solutions of $A-B=C$ and elliptic curves. Number theory (Ulm, 1987), 31--62, Lecture Notes in Math., 1380, Springer, New York-Berlin, 1989. MR 90g:11069 (Reviewer: Kenneth A. Ribet) 11G05 (11D41 14G25 14K07) Frey, G. Links between elliptic curves and solutions of $A-B=C$. J. Indian Math. Soc. (N.S.) 51 (1987), 117--145 (1988). MR 90i:11059 (Reviewer: Kenneth A. Ribet) 11G05 (11D41 14K07 14K15) -Bill DubuqueReturn to Top
a beanReturn to Topwrote: Maybe you should start being a little bit critical about your own question. Let us try to put in a more general context. Have you seen a crystal growing? They do grow symmetrically; all faces and edges grow at the same rate. So maybe symmetry is not a weird thing that happens to snowflakes, but rather it is a general property of crystals. Including water crystals. I know what you are thinking, that I am not addressing your question, but think of this: what is it that, in a "typical" crystal, forces each face and edge and vertex to grow in opposite direction but same speed as the face/edge/vertex at the other side of the crystal? And yet, not all crystals are symmetric. When they are large enough the conditions change a little bit from one side to the other and you get a not-so-perfect crystal, with an edge which is a little bit longer than another. Hey, this sounds familiar, right? People have said that something similar happens to the snowflakes if they grow too large. Sorry, your snowflake.gif is not the end of the story. Somebody put those pictures together to illustrate a point, and because they were pretty. Maybe that person should have added another picture, this one larger, of a snowflake which is visibly unsymmetric in your sense, of not having all the branches with the same structure, to illustrate another point. The thing with snowflakes is that they aren't convex as "typical" crystals, but "spiky". You must have seen how the ice that sometimes forms on your car windshield tends to grow along lines which sometimes branch. The point is, this branching is not continuous but discrete; at some point, for some reason, a spike branches. If they branched continuously, you would get a film of ice covering your windshield, instead of the spiky growth. Well, I don't know what is it that makes one of these spikes to branch. I guess it is a combination of vibration/temperature/ humidity/pressure/somethingelse. But, whatever it is, it is likely to happen simultaneously in the six sides of a _small_ snowflake. You look at your windshield and you see that those spiky crystals do not branch symmetrically at the scale of centimeters. Now, since the six sides in a small snowflake were symmetrical before they branched, the new spikes grow in symmetrical directions. Let me remind you here of the question I made at the beginning: "what is it that forces each edge to grow in opposite direction but same speed as the edge at the other side of the crystal?". The answer, that I guess you know but I'll say anyway, is that since the whole snowflake is one and the same water crystal, its molecules are oriented in the same directions all over the snowflake. (At least if it is small enough.) Look at snowflake.gif and check that all the branching happens at 60 degree angles. Add the hypothesis that typically a snowflake falls to the ground before it grows too large to stop being symmetric, and my point is made. What we need now is somebody to pick up a few large, unsymmetric snowflakes and put them in a bigsnowflake.gif that you can see and ignore because it is not so pretty. So there you have a mechanism which explains why small snowflakes are symmetric. And you are right, I don't know the fine details; I don't know quantum mechanics so I can't explain how water molecules join in a crystal, nor why/how a spike branches. I don't know how much time does it take for a snowflake to fall to the fround, or how much has it grown by then, or what is the typical size of a snowflake before it branches unsymmetrically. I don't have all the answers, you are absolutely so right. But I don't see a bigger question here; why do you think there is one? Have you computed that radius of typical unsymmetry, and it happens to be a lot larger than millimeters? I am sorry if this message has a rather jerkish tone, but somebody has to tell you that you can not say "your model can not work just because". It would really help if you said something more concrete than "there has to be something deeper". Could you please say at which point in the previous explanation do you disagree with us? Santiago
Del StantonReturn to Topwrote in article <5ah6kg$mla@news2.cais.com>... > Posted to the news group and sent to > "J. Clarke" > > Dear John Clark, > > Thank you for your response . . . . > > Hey - I am talking elementary school math. > > And - given truncated decimal values for e and pi - one can > calculate the product using repeated addition. I am talking > about numerical caculations here, and any numerical calculation > must use rational numbers. Given truncated values you can arrive at truncated answers. But a truncated value of pi is no more pi than 3 is 4. Just a useful engineering approximation. > > When I was taught multiplication its relationship to counting by > "n" (counting by twos - counting by threes) was not taught, nor > was the concept of multiplication as repeated addition. It > was another process - separate from addition and subtraction - > that was taught as a rote process. I didn't "understand" > multiplication until years later. Depends on your objectives. If one wants to calculate efficiently, then memorizing the tables is better than knowing how to derive them--9 times 9 is 81 is a lot quicker than 9 plus 9 is 18 plus 9 is 27 plus 9 is 36 plus 9 is 45 plus 9 is 54 plus 9 is 63 plus nine is 72 plus (now let's see, how many nines have I added here--I've lost track--oh, only 8--ok) 9 is 81. Even with computers, table look up is often more efficient than repeated addition. On the other hand, when dealing with computers, repeated addition is a valid way to derive the tables. I was taught this relationship and then tried to apply it instead of memorizing the tables, with the result that I have never completely committed the multiplication tables to memory. Which occasionally annoys me, but not enough to do something about it. --John
Roger Luther (luther@dircon.co.uk) wrote: : The chance of winning is slightly under 14 million to one. 14 MILLION! Whew! I thought you said 40 MILLION!! For a moment there, I thought I might be wasting my money. --Return to Top
Wlodzimierz Holsztynski wrote: > > ; > > > > Polynomials over finite Galois field > spread so evenly across their finite affine space > I wish for a network of friends > to count on > > H.New Mexico > 1996-03-05/06 One thing I hate about certain poets is that they hide their meaning in unfamilar terms(or algebra in this case). Personally, I like the so called generic style, sure more simplistic, yet just as powerful. Consider it postmodernism. I wrote that poem(Inside) as a direct result of reading Emily Dickenson(Miss Original). I appreciate your response to my poem, but I would like to know exactly what you find generic(the content, the style, rhyme). I admit I have a lot to learn, but I gain nothing from your previous comment. I was wondering what exactly are you trying to say in this above blurb. ?you want friends that are reliable as a function you plug numbers into? never met anyone quiet like that. Nothing is consant in this world; all exceptions are only human concoctions(numbers). Pretty generic, right! RBCReturn to Top
-----BEGIN PGP SIGNED MESSAGE----- These articles appeared to be off-topic to the 'bot, who posts these notices as a convenience to the Usenet readers, who may choose to mark these articles as "already read". You can find the software to process these notices with some newsreaders at CancelMoose's[tm] WWW site: http://www.cm.org. Poster breakdown, culled from the From: headers, with byte counts: 2 4699 Archimedes.Plutonium@dartmouth.edu (Archimedes Plutonium) 4699 bytes total. Your size may vary due to header differences. The 'bot does not e-mail these posters and is not affiliated with the several people who choose to do so. @@BEGIN NCM HEADERS Version: 0.93 Issuer: sci.math-NoCeMbot@bwalk.dm.com Type: off-topic Newsgroup: sci.math Action: hide Count: 2 Notice-ID: smncm1997002064047 @@BEGIN NCM BODY <5ahege$64p@dartvax.dartmouth.edu> sci.math sci.physics sci.logic <5ahtbp$c3n@dartvax.dartmouth.edu> sci.math sci.physics sci.logic @@END NCM BODY Feel free to e-mail the 'bot for a copy of its PGP public key or to comment on its criteria for finding off-topic articles. All e-mail will be read by humans. -----BEGIN PGP SIGNATURE----- Version: 2.6 iQCVAwUBMsyp8DLKBVWUZJPVAQFSNAQAkJRbm73hxidr48Pk1yt6ZQ1WqLdQvZUJ Qvj3QHY/UcKbVGSELvm8pDHO6ShhdZUnOJRkkjBYXp7IfHDA08MPz2LTjVOBkoRW dRWojVB0am1RT2pj7EYbIpyLGJgYe7/FqGeZr5DvJmsCvmVsUwyq8BGjngSllCgD SY+1POBEKLk= =x3A2 -----END PGP SIGNATURE-----Return to Top
Jiri Mruzek (jirimruzek@lynx.bc.ca) wrote: : Hmm, yours is an answer in the witty category. I'm unfamiliar with the category of wit. What are the morphisms? Are there any free objects? How about interesting functors to the category of sarcasm? $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 hetherwi@math.wisc.edu $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666Return to Top
Dear mathematicians, Is this newsgroup the forum to seek comments on the relative merits of Mathematica, Maple, Mathcad and the like? If not, can people suggest a newsgroup ? I'd like to know if the products are orientated at different classes of problems, if they are easy to learn, if they have loyal bands of users, if they are available in the public domain, and any other insights users would like to share with me, thanks in advance, David, Melbourne AustraliaReturn to Top
In a previous article, abian@iastate.edu (Alexander Abian) says: >In article <32C06F00.4FFB@slonet.org>, Casey JonesReturn to Topwrote: >>Alexander Abian wrote: > >>> Now, if 0.99999999.... were less than 1.00000000... then >>> >>> (1) p + 0.999999999.... = 1.00000000.... >>> >>> FOR SOME POSITIVE REAL NUMBER p. I suspect at least some of the motivation for the debate on this posting is perceived ambiguity in the notation "0.99999...". If 0.999999... < 1, then 1 - 0.999999... = p > 0, but how "big" should p be if we are permitted to continue the 9's indefinitely? Clearly no matter what positive p you choose >>> >>> p + 0.99999999.... > 1.00000000.... for any p > 0 >>> >>> contradicting (1) and THEREFORE 0.99999999.... = 1.00000000.... >>> No. You have implicitly defined p = 1 - 0.999999... (for the sake of the argument) above, so p + 0.999999... = 1, not > 1. I'm not necessarily questioning your conclusion, just how you got there. Scott McC.
On Sat, 28 Dec 1996, Robert Lewis wrote: > Lenny Schafer wrote: > > > > Your chance of winning the typical big state lottery: 5 million to one. > > -- > > > Aren't most lotteries (in big and small states) a matter of > picking six correct numbers out of a field of fifty? > > Assuming that you bought only one ticket, your chances are > closer to 16 million to one. > Which, incidentally, is exactly as probable as if a UFO would crash into the Eiffel Tower with Elvis as pilot (some brit' said)Return to Top
In article <32C3F6A0.5811@bellsouth.net>, hardenReturn to Topwrote: >I know of a very simple proof of the irrationality of e based on the >factorial series( assume it is rational, set the rational number equal >to the series for e, multiply by the factorial of the denominator( you >can prove from the series that e is positive so you use a positive >integer for both numerator and denominator ), separate the multiplied >series after the term which equaled 1 after the multiplication, and show >that the remainder of the series is between 0 and 1 and therefore not an >integer, whereas everything else was an integer ), but are there any >similar proofs of the transcendence of e based on the Taylor series for >e^n: 1 + n + n^2/2! + n^3/3!... ? Comments would be greatly appreciated. I don't know of any such approach, and doubt it would be possible, since it's quite a different matter to prove a number transcendental. The clearest proof of the transcendence of e that I've encountered was a two-pager in Herstein's _Topics in Algebra_ (2nd ed., pg. 217), that used Hermite polynomials, but required only some familiarity with calculus to understand. --Andrew. -- "I shall drink beer and eat bread in the House of Life."
Eric Postpischil asked "What is the minimum diameter of an undirected graph of n nodes of degree at most d?" (What interesting properties, and other related questions.) Some of your questions are covered in various graph theory texts. I seem to recall one called _Algebraic Graph Theory_ by Biggs, which paid a lot of attention to symmetry. He uses the notion of "girth" instead of diameter, but you can make the adjustment in terminology. One class in matrix theory and some elementary group theory suffice to get you through most of it. I recall the interesting result that there are at most four "regular" graphs of diameter two. Here, regular means each vertex is of the same degree. ( I am speaking of undirected graphs with at most one edge between any two vertices. The degree of a vertex is the number of edges at that vertex. ) Three of these are known, and have interesting symmetry properties. The first is the pentagon, v = 5, d = 2. ( That is, 5 vertices, each of degree 2. ) The next has v = 10 and d = 3. Called Petersen's graph, it is often pictured as a 5-pointed star inside a larger pentagon, with 5 more edges connecting the inner figure to the outer figure in the most direct routes. If you draw this figure, you will see that it indeed has diameter 2, that is, a path of length 2 or less connects each pair of points. It's not hard to see that a regular graph of degree "d" that has diameter 2 will have v = 1 + d^2 vertices. Curiously, v = 5, 10, 50 and possibly 3250 are the only possible graphs of this type, corresponding to d = 2, 3, 7 and posibly 57. Folks (at IBM around 1960) named Hoffman and Singleton discovered the Hoffman - Singleton graph with v = 50 and d = 7. I won't pretend I can describe it, but it includes several copies of the Petersen graph and intricate linkages, and has quite nice symmetry. ( Some texts offer reasonable pictures, check the index. ) Biggs includes a proof of the H-S result, that v = 3250 and d = 57 is the only other possibility. This graph would have 92,625 edges if it exists. It remains undiscovered, as far as I know, but must lack an important symmetry property called "distance transitivity." This is just a short introduction to some of the simplest results. Quite a lot is known about regular graphs of small diameter, and the known ones do have pleasing symmetry. I'm sure there's been work done on the minimum diameter of any graph with v vertices and maximum degree d. (Such graphs tend to be efficient and profitable to Ma Bell and family, so the research is well-funded.) You also asked about "multiple shortest paths." A regular graph of minimal diameter can lack multiple shortest paths. In a sense, it's a waste of edges to have two shortest paths between two nodes. However, since only a few graphs can be perfectly efficient, the rest will have multiple paths between some diametrically opposite nodes. Hope this helps you get started! Patrick T. Wahl ( no institutional affiliation )Return to Top
I have a dilemma : I have a multi-valued (not simple) function y = f(x) I parametrise it as Q = (x(k), y(k)), I then take the power spectra of x(k) and y(k). What is the power spectrum of the original function ? thanks please reply to P.M.Remagnino@rdg.ac.uk PaoloReturn to Top
Angelina Lam asked about the "Mathematics Teacher." The "Mathematics Teacher" is published by the National Council of Teachers of Mathematics, 1906 Association Drive, Reston, Virginia 22091-1593. I think you get it as a side benefit of joining their organization. Try their web page at http://www.nctm.org ( specifically ) http://www.nctm.org/member_services/MEMBENEF.HTM for more info. If you want just the magazine, they answer questions in e-mail to InfoCentral@nctm.org I got the above off web pages; I don't speak for them. Patrick T. Wahl ( no institutional affiliation )Return to Top
I am interested in knowing about algorithms for converting a covariant tensor to a contravariant one and vice versa. I know that for tensors of rank n and indices i_1, i_2, ..., i_n = 1..2, this can be achieved by inner product of the tensor with the permutation tensor, e, defined by, _ | 1 if i=1, j=2 e_ij = { -1 if i=2, j=1 | 0 if i=j - In a general case when i_1, i_2, ..., i_n = 1..r, how can we achieve this transformation from covariant to contravariant tensor and vice versa ? Thanks SatishReturn to Top
Oops, I gave you a typo. The equation for E(y_k) has a sum for j=1..y, not 1..n: E(y_k)=C(n,k)*sum[j=1..y]{(p_j^k)*(1-p_j)^(n-k)}, which amounts to a different proportionality constant (y instead of n) if p_j=1/y. Your results become 48884 = y * n * 1/y * (1-1/y)^(n-1) 208 = y * (n-1) / 2 * n * 1/y^2 * (1-1/y)^(n-2) 5 = y * (n-1) * (n-2) / 6 * n * 1/y^3 * (1-1/y)^(n-3) etc. Since you then take ratios, your argument is not affected by the typo. -- Robert E Sawyer soen@pacbell.netReturn to Top
Gail wrote: > > I have a math report due this Monday (1/6/97) in which I have to write a > short essay on Diophantus and al-Khowarizmi. I have barely found any > information so I would appreciate if I could get some help on the > mathematicians or places where I could get some info. > > Jon > > PS. E-mail me at Mr Wuggum@aol.com or Tuzbubble@aol.com > > PPS. Pleeeeeeeeeeeeeeeez? Hie, You can find the strange link between al-Khowarizmi and algorithm in the book : The Art of computer programming by Knuth vol : 1. Very interesting and some references. You can also get a picture of him at the home page of Knuth http://www-cs-staff.stanford.edu/~knuth/index.html Of course there is also many things on the web for exemple http://aleph0.clarku.edu/~djoyce/mathhist/chronology.html Good Luck. P. Langevin.Return to Top
3.95.970103085014.470B-100000@rubin.but.auc.dk> Organization: Insignia Solutions In articleReturn to Top, Nikolaj Toft Hansen <31nik@but.auc.dk> wrote: > On Sat, 28 Dec 1996, Robert Lewis wrote: > > > Lenny Schafer wrote: > > > > > > Your chance of winning the typical big state lottery: 5 million to one. > > > -- > > > > > > Aren't most lotteries (in big and small states) a matter of > > picking six correct numbers out of a field of fifty? > > > > Assuming that you bought only one ticket, your chances are > > closer to 16 million to one. > > > Which, incidentally, is exactly as probable as if a UFO would crash into > the Eiffel Tower with Elvis as pilot (some brit' said) The version that I heard was a british bookmaker saying that the only bet that pays 14 million to one was that an UFO with Elvis on board crashes on the Loch Ness monster. My favorite comparison is: In Britain, if you buy twentyeight tickets each week, your chances of winning in the national lottery and your chances of being killed in a traffic accident are about the same.
Hi folks. I am a student of The University of Gothenburg in Sweden. Please help me with this problem and I would be very grateful... Proof that: 13 divides (17^47 + 2^12)^14 -4 Please, do not suggest me to use a computer or a calculator (17^47 is quite a large number). //JacobReturn to Top
U Lange (lange@gpu4.srv.ualberta.ca) wrote: : : * How much agreement is there among mathematicians about beauty : : and elegance of theorems and proofs? Where does this agreement : : come from? Zero. The "beauty" or "elegance" of a proof is strictly in the mind of the person viewing the proof. All proofs can, subject to the conditions of a sufficient quantity of time and paper, be reduced to formal, logical, axiomatic statements. Hence, different proofs of the same theorem reduce to the same set of symbols for a given formal system. Therefore, it is only in a person's mind about "elegance". There is certainly no outside objective measure of elegance and beauty.Return to Top
31-12-96 revised 1-1-97 Notes on the structure of reality - article 3 (first draft) by Gary Forbat Copyright (c) G. Forbat 1996 It may now be convenient to extend and qualify some of the main concepts derived from the theory. In the previous essays I described a process of material formation which provides the basis for the observed material reality. The process operates through a building procedure which involves a relationship between the physical magnitudes of structures, that is, the volume they occupy, and the rapidity of their internal cycles. Moreover, the process is universal, ranging over an infinity of scale tranformations from the most miniscule sizes to the most gigantic imaginable, in fact infinite in both directions. But it is not a single dimensional process involving only scale. What is peculiar about the sequence is that the smaller structures of the micro world are highly dynamic due to an extremely rapid internal cycle operating to hold it together, and the smaller the structure, the more dynamic it is. Dynamics refers to the rapidity of the cyclical pulse. As particles break down to the cyclical funtion of a number of smaller components, those components will have a significantly more rapid internal cyclical rate than those of the larger structure they contribute to forming. The atomic structure, for instance, comes into being due to the cyclical function of the electron in relation to the nucleus. The composition of the electron has not yet been penetrated, but the possibilities are few. Either it is composed of a very large number of tiny parts, or maybe fewer but of a much higher dynamicity. The nucleus, on the other hand, is known to break down to combinations of smaller, but much more dynamic parts known as 'quarks'. Quarks themselves must reduce to even smaller components, with cyclical rates of increasingly more rapidity. The many qualities of quarks testify to a variance of configurations. The quantum proportions testify to this very nature. With the process of reduction infinite, so with it is the increase in dynamicity. We are fortunate enough to be able to observe two vastly different aspect of the material process. The micro scales of phenomena present an integrated view of average behaviour over many billions of cycles. Imagine how the solar system would look if billions of planetary cycles were pressed into a single second. Theoretically at least, it would be possible to simulate the effect by taking a long term video of the solar system in motion over many billions of years, and then replaying the tape over a matter of seconds. Undoubtedly we could make computer image simulations of it much more easily. Then there is the almost static view of the process presented by the structures of the large scale in their 'real time' cyclical movements. Our viewpoint of stellar formations is fashioned from the workings of the atomic structure, and compared to the speed and capacity of the functioning of our instruments and sensing apparatus, the stellar structures are both extremely large and so slowly evolving as to be almost static. But now, let's venture to reconstruct in its broadest principles the consequences of this infinite sequence of structuring, not only to determine the status of our own viewpoint within it, but to attempt to discover general principles that may be directly affecting us and we are not yet aware of. Firstly, going up or down in scale, the specific attributes of structure types that occur depend on the interactive possibilities afforded on each particular scale. Solar systems of one type or another, whether binary or planetary are the almost exclusive forms that may be found at the scale of the direct interaction between the most massive atomic conglomerations. At this scale of consideration the universe can be seen to be interspersed with stellar and planetary matter in mutual interaction as solar systems. But we know that solar systems, in turn, almost exclusively congregate in the larger massive formations of galaxies, occuring in a small number of types. Galaxies themseves form clusters with unique characteristics types of their own. On the galactic scale of consideration the universe can be seen as interspersed almost exclusively by galactic formations. Certainly they are the only long term stable forms to be found at this scale. In fact we can apply this principle at any level of magnitude. Thus the universe is interspersed by atoms at the atomic scale of consideration but with planetary/stellar matter on a larger scale. So then, as the process builds to infinity, with each structure type occuring in forms and attributes appropriate to interaction and formation possibilities at that scale. Each transformation produces unique structure types, and there is certainly no likelyhood of the same structure type occuring at different levels either in the micro and macro scales. Both the reduction and its reverse process of expansion runs to infinity, with the roots of each or any structure traceable in infinite steps toward smaller scales. But this does not work in the reverse toward the macro. The reason is that not all structures continue to build outward forever. Large sections of it terminate at a certain level, as in the case of the structures that intersperse in our seemingly empty spatial regions. My findings are that these regions are far from empty. The entire spatiality in fact contains a fine invisible mist of matter, structured at its highest level to an interactive fabric to form a micro infrastructure which sets the framework for the workings of our atomic based matterial environment. But only those elements which participate in further building processes to form the atomic base can get through to build outward to form structures on larger scales. The rest, indeed a very large portion of micro material, is lost to further structuring. In this infinite chain of expansions it should be expected that terminal stages are reached from time to time. Nevertheless, what remains after each of these mass terminations is still adequete to reconstruct other equally thickly populated levels of structures on much larger scales. So what is the status of our material system amid this infinity of transformation levels ? On the micro end we observe the process through a very high integration, but on the macro end it tends toward static. With the two directions reflecting merely different aspects of a single process, our observational access results from the circumstances of our evolution as sensing beings and our relation to the material interaction that brought it about. We are a direct product of our micro infrastructure and the atomic base. The question remains whether ours is the only material environment possible or whether there may be others ? Perhaps other configurational circumstances can exist among an infinity of types which produces alternative material bases. We need firstly to examine the general circumstances which must be present for a material environment. Obviously the most evident is the versatility of our atomic structure. It is extremely stable and durabile with, stability, regularity, as well as variability in chemical combination. It is truly like a wonder particle which goes on to create a tremendously varied and interactive world of material activity. Surely it would be fairly rare to find a scale level of structuring where such a useful type of particle is found. Nevertheless it stands to reason that in a infinite chain of transformations other similarly efficient structure types are bound to occur. some may indeed be even more flexible than the atom, or perhaps somewhat less so, but still able to generate a causal evolution in its conglomerate forms to create an alternative material environment rivalling ours. Of course on the micro scales a funtional world would evolve extremely rapidly compared to ours, and on the macro scales the events would take on gigantic proportions, evolving very slowly by our way of looking at it. G. Forbat to be continued in the next articleReturn to Top
DavidReturn to Topwrote: > > Jacob Martin wrote: > > >Think you're a good mathematician? Then check out > >www.jmartin.home.ml.org for a selection of maths problems in the maths > > I did try http://www.jmartin.home.ml.org > > Got to a site that was just a pointer. Went to the pointed site, to > find that entry was FORBIDDEN. Not interested in fame (but could use > the Fortune,) just curious. I tried it and located the page at http://www.geocities.com/CapeCanaveral/7950/main.htm . It still may be FORBIDDEN to some places, but this URL worked for me (for example, there was a link to a math. page there). -- -- Vincent Johns Please feel free to quote anything I say here.
Short course in CFD in Combustion Engineering, at University of Leeds, UK - 3 - 4 March 1997. Further details from: Jamie Strachan Dept of Fuel and Energy University of Leeds LEEDS LS2 9JT Email: shortfuel@leeds.ac.uk Tel: + 44 (0) 113 233 2494 Fax: + 44 (0) 113 233 2511Return to Top
Angel Garcia wrote: > I worked out (at 17: thus elementarily) the cubic equation which > is fulfiled by the side of inscribed convex heptagon (angle 2*pi/7). > I can post it here if it is of some interest. The solution has two > complex-conjugate solutions plus the real solution, of course; which > only can be obtained in terms of cubic roots and therefore it cannot > geometrically be constructed via Plato's tools (ruler & compass). > But in any case the solution can be expressed explicitly in terms > of two relatively simple cubic roots with complex radicands. In the recent "The Book of Numbers" (Springer 1996) Conway and Guy give constructions for regular 7, 9 and 13-gons using straightedge, compass and angle trisector. The heptagon construction is amazingly neat. -- Robin J. Chapman Department of Mathematics "But there are full professors University of Exeter, EX4 4QE, UK in this place who read nothing rjc@maths.exeter.ac.uk but cereal boxes." http://www.maths.ex.ac.uk/~rjc/rjc.html Don Delillo--White NoiseReturn to Top
: My view is that math is largely independant from reality, Number one: Math IS reality. It really DOES exist. Of course, I am allowing ABTRACTIONS to exist. It exists regardless of whether anyone is there to think it. I assume that this is what you mean by "independent from reality". Number two: ANY other subject (that might qualify as a major at a university, for instance) ALSO using abstractions to describe it. It's called LANGUAGE. Number three: Math is, by far, infinitely better suited at describing ALL of reality, not just part of it, than all the subjects referred to in "Number two". : it is best applied to the abstractions and mental models we : made of real things. That's because that's the only thing math CAN be applied to: the abstractions and mental models we make of things. Again, EVERY human subject, with its corresponding language and terminology, can only be applied to an abstraction in our heads. This is good because even the simplest things : from reality are so complex that we wouldn't be able to cope with : them. Yes. Just as doctors and lawyers and judges make simplifying models in their mind to achieve an end such as reaching a decision. Reality is by nature three dimensional, so I don't it is : possible to build a 2 dimensional figure in reality, the lines you : draw will be made of atoms which are three dimensional. : I don't think it is possible to build even ideal polyhedra. Of course not. NO one can create EXACTLY what is in their mind. The greatest sculptors and artists cannot do it. What they create is their very best approximation to what's in their minds. "Best" means "optimal subject to the condition that they wish to reach a decision in a finite amount of time" (and effort).Return to Top
Schleeha (schleeha@aol.com) wrote: : There is nothing defamatory about expressing the opinions about the : legality of an offer. More strongly: there is absolutely nothing illegal about expressing an opinion about the legality of anything. e.g. It is perfectly legal for a person to express the belief that shooting the President is legal (e.g. they think the President does some much greater harm to the country). People who express such opinions for a fee have a name: they're called lawyers.Return to Top
In article <5ainlm$j3m@earth.njcc.com>, John NahayReturn to Topwrote: >U Lange (lange@gpu4.srv.ualberta.ca) wrote: >: : * How much agreement is there among mathematicians about beauty >: : and elegance of theorems and proofs? Where does this agreement >: : come from? >Zero. The "beauty" or "elegance" of a proof is strictly in the mind >of the person viewing the proof. All proofs can, subject to the conditions >of a sufficient quantity of time and paper, be reduced to formal, logical, >axiomatic statements. Hence, different proofs of the same theorem reduce >to the same set of symbols for a given formal system. Therefore, it is >only in a person's mind about "elegance". There is certainly no outside >objective measure of elegance and beauty. There are different ideas of beauty and elegance. An elegant proof may give little understanding of the theorem; witness the proof of the Fundamental Theorem of Algebra using Liouville's Theorem. It is extremely short, but a powerful deus from a powerful machina has been invoked. A good proof should provide insight. The proof using induction on the highest power of 2 dividing the degree of the equation requires a lot of machinery as well, and may very well be the most insightful one I know. But if we taught the structure of the real numbers, and the ideas of continuity needed even to understand infinite decimals, we could just show that the minimum absolute value is attained and it being non-zero leads to a contradiction. In probability, I consider elegant proofs using transforms of any kind as relatively unenlightening. This does not mean that I do not use them; I consider these to be very important for obtaining numerical answers, and it is often the case that proofs which give more insight are not readily available. -- This address is for information only. I do not claim that these views are those of the Statistics Department or of Purdue University. Herman Rubin, Dept. of Statistics, Purdue Univ., West Lafayette IN47907-1399 hrubin@stat.purdue.edu Phone: (317)494-6054 FAX: (317)494-0558
John NahayReturn to Topwrote: > > U Lange (lange@gpu4.srv.ualberta.ca) wrote: > : : * How much agreement is there among mathematicians about beauty > : : and elegance of theorems and proofs? Where does this agreement > : : come from? > > Zero. The "beauty" or "elegance" of a proof is strictly in the mind > of the person viewing the proof. All proofs can, subject to the conditions > of a sufficient quantity of time and paper, be reduced to formal, logical, > axiomatic statements. Hence, different proofs of the same theorem reduce > to the same set of symbols for a given formal system. Therefore, it is > only in a person's mind about "elegance". There is certainly no outside > objective measure of elegance and beauty. I do not completely agree. There are criteria that are generally accepted for judging a proof "elegant". I can't formulate all of them, but you are already aware of some of them, such as conciseness and clarity. (I am excluding correctness here, since otherwise you have a "poof", not a proof.) Conciseness can be measured mechanically, by a computer -- all you need to do to compare two proofs on that dimension is to count the symbols employed in expressing it. The lower number wins. Although the relative importance of such criteria is a matter of individual taste, their existence is less so (i.e., many of these are shared values, and for good reason). I would be interested in seeing the canonical "same set of symbols for a given formal system" for, for example, the Pythagorean Theorem. Hundreds of proofs have been published for this theorem (as I understand it; many of them I have not read); they are all equivalent, I suppose, in the sense that they are valid arguments, but is it really true that each of them can be expressed in exactly the same set of symbols? What do the diagrams look like, as expressed in this common set of symbols? Saying that there is "certainly" no outside objective measure of elegance and beauty piques my curiosity; I would be interested in a proof of this assertion. I understand that there are subjective parts of a determination of beauty, but there are also aspects that are widely recognized and shared. Editing a fashion magazine, IMHO, is not a totally random process (beauty of the photographs to be published must be considered), and neither is editing a mathematics journal. I think I would say to U Lange that there is definitely some agreement (not necessarily total) about which proofs are most pleasing, and that this agreement originates in personal feelings about how easy the proof is to understand, how quickly it can be read, etc. It then migrates (via personal discussions or published papers) to a consensus within the interested community, as people who have seen the proof and are not shy about revealing their emotional reactions to it share their feelings with each other. For example, someone might say, "Did you see John Doe's new proof of Exwyezee's Conjecture? It looks correct, but I think he could have used the ___ Theorem to shorten his proof of Lemma 2." BTW, the same sorts of criteria that I mentioned as applying to people's emotional responses to proofs apply as well to computer algorithms. Of two correct ones, one might be far easier to understand, shorter, etc., than the other one, and (assuming that it has been demonstrated that both are correct) it should not take an expert to determine which is better written. -- -- Vincent Johns Please feel free to quote anything I say here.
Brian Lui wrote: > What about this... it's really basic but it caught me out... > > a = b > > 3a - 2a = 3b - 2b > > 3a - 3b = 2a - 2b > > 3(a-b) = 2(a-b) > ^^^ ^^^ > 3 = 2 > -- The error is that you can't divide by (a-b) since it equals 0. HaranReturn to Top
David wrote: > Jacob MartinReturn to Topwrote: > >Think you're a good mathematician? Then check out > >www.jmartin.home.ml.org for a selection of maths problems in the maths > I did try http://www.jmartin.home.ml.org > Got to a site that was just a pointer. Went to the pointed site, to > find that entry was FORBIDDEN. Not interested in fame (but could use > the Fortune,) just curious. Hello, I just tried this and had no trouble. I was not FORBIDDEN. I found 9 problems (as well as other things). It promises more and harder problems to come, along with honorable mention. Dan
Given: A set of threedimensional coordinates identifying points on the surface of the spheroid with the radius r. Wanted: The maximum volume of the sum of tetraeders formed by three surface points and the center point of the spheroid (= origin of coordinate system). Restriktion: Each volume element must contribute only once! With infinite points on the surface the volume must result in the spheroidal volume! Problem: It exists many combinations of tetraeders. Which strategy or algorithm will lead to the maximized volume of all tetraeders? Example of the problem: Choose four surface points plus the origin. With these five points two sets of two different tetraeders can be formed. Which set has a larger volume? Ok. You might say: just calculate it and you'll know it. That's true. But if an additional point appears I obtain much more possibilities of tetraeders. Where do I start? Which possibility leads to the maximum volume? ---??? Exactly, that is my problem. Hope to get an answer from the sci.math community. Please mail me: hase@wettzell.ifag.de -- *********************************************************************** * Hayo Hase Tel: 09941-603-0 * * Institut fuer Angewandte Geodaesie Tel: 09941-603-104 * * Fundamentalstation Wettzell Fax: 09941-603-222 * * D-93444 Koetzting Net: hase@wettzell.ifag.de * ***********************************************************************Return to Top
In article <32cc24f6.7396859@news>, Greg RatzelReturn to Topwrites >On Thu, 2 Jan 1997 16:07:04 +0000, Gary Hampson > wrote: >>1) The function you describe as a time/space domain operation is simply >>some weighting function of f(t). Similar to say Hamming or Hanning >>window functions. On that basis its frequency domain equivalent is a >>convolution with its fourier transform. > >I disagree. g(sigma) is more complicated than a window function. >Window functions are multiplied by the time-domain function, so the >corresponding frequency domain operation is convolution. On more than 3 seconds reflection I agree, as they say "engage brain before opening mouth", gone off half cocked.... and all that stuff. -- Gary Hampson
In articleReturn to Top, Nikolaj Toft Hansen <31nik@but.auc.dk> writes >On Sat, 28 Dec 1996, Robert Lewis wrote: > >> Lenny Schafer wrote: >> > >> > Your chance of winning the typical big state lottery: 5 million to one. >> > -- >> >> >> Aren't most lotteries (in big and small states) a matter of >> picking six correct numbers out of a field of fifty? >> >> Assuming that you bought only one ticket, your chances are >> closer to 16 million to one. >> 6 from 50 possible numbers is actually 1 in 13,983,816 which is as stated earlier, slightly less than 1 in 14 million. Where does your 16 million figure come from ? Or could it be that you are more of a pessimist than I .... ;) -- Gary Hampson
In article <32C90B5C.64B1@public.ibercaja.es>, benignoReturn to Topwrites >Hi, > I need to handle Big matrix of around 800 x 800 to implement > some optimization algorithms, I would use C++ libraries if > possible to use on BorlandC++ 4.5, but if there is any shareware Unless the matrix has some structure which allows many short cuts and reduced storage (eg Toeplitz), then just get on with coding it. 800*800 is not that big (unless of course in the optimisation you need to evaluate A.x many times, or you have some time critical conditions. -- Gary Hampson
In articleReturn to Top, Christopher Gordon writes >Hi, > >Is it possible to analytically express the probability distribution for > >c = a / b > >where a and b are univariate independent normally distributed random variables. > >I worked out the case when they both have 0 means, then c is Cauchy >distributed. >However when b has a zero mean and a has a nonzero mean, I end up with >having to evaluate integrals of the form > >\int_0^\infinity exp(-A x^2 + B x) dx > >with A > 0. > Dear Chris, I had the same problem. I found 2 ways around it. 1) Get help with the stinking integrals (the first time "help" enjoys the novelty, if i>1 then "help" mysteriously disappears) 2) I generated a few thousand samples of a(i)/b(i) with a and b appropriately distributed and then plotted the histogram of c and assumed it was the populations pdf. -- Gary Hampson
In article <560tlm$nih@gap.cco.caltech.edu> ikastan@alumnae.caltech.edu (Ilias Kastanas) wrote: : :In article <19961108163000.LAA25851@ladder01.news.aol.com>, :Return to Topwrote: :>In article <55rq1t$963@nuke.csu.net> :>Ilias Kastanas wrote: :>> :>> So in Mr. Tleko's world there are no analytic functions at all .... :> :> There are. e^z is analytic in the whole plane. :> : Good, but if e^z = R + iI then according to your "formula", : : e^z = sqrt(R^2 + I^2) * (cos(atan(I/R)) + i*sin(atan(I/R)) . : : So then, pursuing your "argument", the multiplicity of arctan means that : e^z is not analytic! The formula for e^z you wrote should read: e^z=e^(x+iy)=(e^x)*(e^(iy))=(e^x)*(cos(y)+isin(y)) where R=(e^x)*cos(y) and I=(e^x)*sin(y). There is no arctan involved and e^z is an analytic function. Please make a note of it. tleko@aol.com
Hello, I am looking for informations about methods to inverse a matrix ; but only the ones which are using random numbers. Any information will be appreciated. Thanks Martial Tarizzo Physics Teacher tarizzo@worldnet.frReturn to Top
Note: ^L indicates a line break on the line above. The line breaks divide this post into 4 pages below The first 2 pages have been changed somewhat from before. Pages 3 and 4 show the numbered words and their algebra for 4 variables related to car travel. ------------------------------------------------------------ The Numbered Word Solution Form And Its Algebra Solves Constant Rate Problems Effectively. Introduction: ------------ Numbered words--in fractions--is a powerful way to examine the numerous physical properties of the world that form constant rates and to solve related problems clearly, easily and concisely. Unfortunately, many k-12 math texts have numerous unrelated forms to solve various constant rate problems. By solving one simple type of problem in many disconnected ways not only creates unnecessary hardships for students and teachers, but makes it unlikely to connect these key ideas about constant rates to geometry, algebra and physical science. A Brief Description Of Numbered Words: ------------------------------------- A numbered word is usually a number next to the left of a word (or abbreviation). The number tells how many, while the word reveals what items are under consideration. For example, "5 pounds" (5 lb) or "4 fruit" are numbered words. A pound is a standard unit of measurement that's counted. Each unit is the same amount of weight. A fruit is a unit that's counted also, but it is not a standard and each piece could be different or identical. In terms of fractions, the pound is uniformly subdivided while a fruit could be cut into any sized pieces. These pieces are counted also to make fractions. Show 2 times 3 with numbered words and related pictures: ------------------------------------------------------- Given: 2 ones 1 ------- 1 1 group 3 groups 1 1 1 1 1 1 Find: Multiply 2 X 3 using numbered words in Solution Form. Show the Found Rate. 2 ones (3 groups) ------- = 6 ones 1 group Found rate: 6 ones / 3 groups The 3 Model Word Forms Below Explain Numbers In Division: --------------------------------------------------------- Name | Arithmetic | Numbered Word Forms -----------------|-------------|---------------------------- Solution Form | 3 (8) | 3 ones 8 groups | --- = ? | -------- = 12 ones (For calculation)| 2 | 2 groups _________________|_____________|____________________________ Proportion Form | 3 ? | 3 ones 12 ones | --- = --- | -------- = -------- | 2 8 | 2 groups 8 groups (For meaning by | |---------------------------- naming rates) | | Given Rate = Found Rate _________________|_____________|____________________________ Division Form | 12 ? | 12 ones 1.5 ones | --- = --- | -------- = ---------- (For unit rate) | 8 1 | 8 groups 1 group -----------------|-------------|---------------------------- Note: | 1.5 | 1.5 ones | ---- = 1.5 | -------- = 1.5 ones | 1 | group -----------------|-------------|---------------------------- Note: The Found Rate shown below usually need not be written but should be clearly understood. Given: 3 dollars ($) per 2 gallons (gal) Find: 1. How many dollars for 7 gallons? 2. How many gallons for $5? 3. Find the 2 possible unit rates. Answer Found Rate |---------| Solution: 1. $ 3 (7 gal) |--------| | $ 10.50 | ----- = | $10.50 | | ------- | 2 gal |--------| | 7 gal | |---------| |---------| 2. 2 gal ($ 5) |---------| | 3.33 gal| ----- = | 3.33 gal| | ------- | $ 3 |---------| | $5 | |---------| |-------------| 3a. $ 3 / 2 gal = | $ 1.50 / gal| |-------------| The unit rate above is called, "the Unit Price". |---------------| 3b. 2 gal / $ 3 = |.667 gal / $ 1 | |---------------| The unit rate above reads as follows: ".667 pounds per dollar". Note that the numbered word solution form above not only easily solves constant rate problems clearly and concisely, but it also reveals the problem solved. The numbered word solution form is a valuable tool for thinking efficiently about relationships between physical properties, presenting solutions to others effectively, and understanding and creating equations as shown below. Given: Speed: S = d / t = [S] miles / 1 hour = [S] mi/hr (Note: Speed is a Unit Rate.) Variables: Distance (d) Time (t) Values: 205 mi 3.25 hr Find: Use the numbered word solution form first, then write below each numbered word part, the proper variable. 1. Find the distance traveled in 4.5 hours. 2. Find the time to go 365 miles. 3. Then find the average speed in miles per hour. Solution: 1. 205 mi (4.5 hours) [d] mi ------- = = d 3.25 hr S t = d 2. 3.25 hr (365 mi) ------- = [t] hr = t 205 mi (1/S) d = t or d/S = t 3. 205 mi ------ = [S] mi/hr = S 3.25 hr d/t = S ---------------------------------------------------------- Given: Gasoline Unit Price: U = C / V = [U] $/gal Variables: | Cost (C) | Volume (V) Values: | $15.93 | 7.85 gal Find: 1. Find cost to fill a 12 gal tank. Use solution form. 2. Find the unit price in dollars per gallon. Solution: Solve Below. 1. 2. ------------------------------------------------------------ Given: Car efficiency: E = d / V Variables: | Volume (V) | Distance (d) Values: | 14.95 gal | 205 mi Find: Find the efficiency in miles per gallon. Solution: ------------------------------------------------------------ Constant rates can be multiplied together to create new constant rates. Note below how the same word in top of the fractions (multiplied together) cancels the same word in bottom of the fractions. This is true for the same variable (or same letter) too. Given: The answers to the 3 above unit rates follow: S = d / t U = C / V E = d / V S = 63.07 mi/hr U = $ 2.029 /gal E = 13.71 mi/gal Find: 1. Volume per time = V/t = F = [F] gal/hr = Flow 2. Cost per distance = C/d = O = [O] $/mi 3. Cost per time = C/t = X = [X] $/hr 1a. 63.07 mi gal [F] gal -------- --------- = ------- hr 13.71 mi hr 1b. d V V --- --- = --- = F t d t S / E = F Challenge: Solve 2 and 3 like 1 above. Given: S = d / t U = C / V E = d / V S = 63.07 mi/hr U = $ 2.029 /gal E = 13.71 mi/gal ---------------------------------------------------------- Given: 2 boys (B) per 3 girls (G) 2 B and 3 G per group (R), 5 people (P) per group group structure G-B-G-B-G or B-B-G-G-G 2 aluminum atoms (Al) per 3 oxygen atoms (O) 2 Al and 3 O atoms per molecule (Al203) Note: The numbers 2 and 3 in Al2O3 should be subscripts. 5 atoms per molecule Find: Using the numbered word solution form, find: 1. How many girls if 6 boys present? 2. How many people if 6 boys present? 3. How many groups if 6 boys present? 4. Check answers 1 to 3 by drawing the number of groups present in the form B-B-G-G-G . Then Consider 5 next: 5. If 6 boys represent 6 Al atoms then how many O atoms, total atoms and molecules are present? 6. Find all 12 different unit rates among B, G, R, & P. ------------------------------------------------------------ If you are interested in promoting constant rate solutions in the K-12 school system (or elsewhere) using numbered words as outlined above (and more to come), please e-mail me your interests on this matter. Thanks. ----------------------------------------------------------- C by David Kaufman, Jan. 3, 1997 Remember: Appreciate Each Moment's Opportunities To BE Good, Do Good, Be One, And Go Jolly. -- davk@netcom.comReturn to Top
In article <32CCB44D.12D7@scf.usc.edu>, Ryan CormneyReturn to Topwrote: >Wlodzimierz Holsztynski wrote: >> >> ; >> >> >> >> Polynomials over finite Galois field >> spread so evenly across their finite affine space >> I wish for a network of friends >> to count on >> >> H.New Mexico >> 1996-03-05/06 >One thing I hate about certain poets Hate? Take it easy. >is that they hide their meaning in >unfamilar terms(or algebra in this case). You show lack of understanding (of poetry I mean, not mathematics). > Personally, I like the so >called generic style, sure more simplistic, yet just as powerful. >Consider it postmodernism. I wrote that poem(Inside) as a direct result >of reading Emily Dickenson(Miss Original). I appreciate your response to >my poem, but I would like to know exactly what you find generic(the >content, the style, rhyme). Where do you have your poem? OK, I'll provide a copy for rap: Ryan Cormney wrote: > > Inside > > Lying next to heart of heat > Waiting for the moment we meet > Side by Side the wall divides > A pulse of blood...we collide > Next to you my muscle stiffens > Inside you my pulse quickens > I look to you for hope and pride > Inside I shall reside... > For Inside you I can confide. RBC 1995 > > This is one of the many poems I wrote for my girlfriend. For all we know from your poem, your girlfriend can be a sheep. > I admit I have a lot to learn, I agree. > but I gain nothing from your previous comment. Poetry is not for everybody. > I was wondering what exactly are you trying to say in this above blurb. >?you want friends that are reliable as a function you plug numbers into? >never met anyone quiet like that. Nothing is consant in this world; all >exceptions are only human concoctions(numbers). Pretty generic, right! >RBC Wrong. Don't worry about what *I* am trying to say. Who cares? Just read. And don't worry about math. My blurb is not any algebra texbook. My blurb is a poem. I might say more if there is any interest... but it's no fun. Enough to say that there is more in my poem than meets the eye even of a reader much more trained and sensitive to poetry than you. Wlod