![]() |
![]() |
Back |
I received the folowing from a gentleman :). > > I couldn't follow your question posted in the news > > A={f/f:[0,1]->R, f continuous and f-1(y) is a perfect set} > > what is f-1(y)? is that f as a subset of R^2 less the identity function > as a subset of R^2 or is it the (f-1) image of some (not defined in your > problem) set y or yet some other thing I haven't thought of? f-1(y) is the set of exes such that f(x)=y (the trivial sense) assume we are only refering to those ys in Im(f) or accept the empty set as perfect. DO NOT assume f onto. Sorry no superscripts :( > also, there are many definitions of perfect floating around. it would > help if you specified. Perfect set = any point is a limit point (A=A') ie if A is a perfect set and x in A there is a sequence (not constantly x starting from any n) which converges to x.) I hope this makes it clear.Return to Top
Patrick T. Wahl (ptwahl@aol.com) reminded me that there's more in Knuth Vol 2 than I thought: the exercises. The Hurwitz doubling formula was intriguing, but I couldn't squeeze out the info I needed. At first blush, doubling the value halves the early partial quotients and doubles others -- but trying to follow through on the recursion succumbs to combinatorial explosion based on odd/even of the quotients. When I checked my vast collection of CF expansions for powers of 2 and 5, I came across the following sequence of doublings: pwr of 5 pwr of 2 #terms max q 16026 37209 21807 178546 16026 37210 21700 1074639800 16026 37211 21821 43355 So doubling 2^37209/5^16026 multiplies some partial quotient by more than 6000; doubling again causes the largest partial quotient to shrink by a factor of nearly 25000. I then checked the Yao&Knuth; reference on the sum of partial quotients, "A.C. Yao and D.E.Knuth, Proc. Nat. Acad. Sci. 72 (1975), 4720-4722". Their formula gives an unusably-large bound for CF(m/n) where m < n: sum < 1.4 * n (log n)^2 + O(n log n log log n) When n has 10000 digits, the bound on the sum exceeds n by a factor of over 20, yet I'm looking for a bound that is *much* smaller. The Yao&Knuth; bound is for all m < n, which includes 1/n, so the bound is certainly going to exceed n. For the particular case of 2^a/5^b where the ratio is nearly 1, the largest partial quotients I came across had 10 digits, even though the original numerator and denominator had up to 23000 digits. The behaviour of CF(2^a/5^b) reminds me of the generalised Catalan conjecture and Tijdeman's bounds -- I wonder if this might be related. (I've heard of Ribenboim's book on the subject, but haven't located a copy yet. I have Alf vanderPoorten's Notes on FLT.) Michel.Return to Top
* The probability of the next one being red is still 50%. The chances of Well, it would help to know how many squares are on a roullette wheel. -- JZS 3=)Return to Top
In 1965, Oxford University Press published an english translation of S.G.Mikhlin's book "Multidimensional singular integrals and integral equations". Since that was 30 years ago, it seems possible that the book has been superceded by a more recent work. I haven't read the book myself, so I can't be more specific as to content. But before I exert myself to try to obtain a copy, I would be interested in knowing its relationship to more recent literature. Allan Adler adler@pulsar.cs.wku.eduReturn to Top
In article <5bb85v$m7p@gap.cco.caltech.edu>, Ilias KastanasReturn to Topwrote: >In article , >Alexander Abian wrote: >> Abian answers: Dear Mr.Kastanas, First of all thank you for your informative e-mail. However, I still tend to believe that with very clever choices for postes and extremely clever usage of dense subsets - the language of Forcing can be avoided. I would like to see if you can consider proving the following two statements in a straight forward way using suitable posets and their dense subsets. Let M be Cohen's minimal model. Let us assume that we DO NOT ^^^^^^^^^^^^^^^^^^^^^^^^^^^^ KNOW THAT CH and Zorn's Lemma are valid in M. ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ (1) Can you prove that some generic extension of M would be a model for ZF+ CH ? (2) Can you prove that some generic extension of M would be a model for ZF + Zorn's Lemma (preferably Zorn's Lemma and not its equivalent AC)? A clear proofs will be greatly appreciated. Thank you -- -------------------------------------------------------------------------- ABIAN MASS-TIME EQUIVALENCE FORMULA m = Mo(1-exp(T/(kT-Mo))) Abian units. ALTER EARTH'S ORBIT AND TILT - STOP GLOBAL DISASTERS AND EPIDEMICS ALTER THE SOLAR SYSTEM. REORBIT VENUS INTO A NEAR EARTH-LIKE ORBIT TO CREATE A BORN AGAIN EARTH (1990)
Keith Pitcher (kpitcher@weirdness.com) wrote: : : My sister realized that this was a trick question, as she knew a piece : of paper can : not be folded that many times in half, and so far every question had : been based in reality. She came up with this description of her answer : Okay, so I made a few calculations on the feasibility of folding a sheet 25 times, and if my rough estimate is correct, the resulting stack would be no less than 3 miles high, under the presumption that we can get paper of thickness 2000 sheets/foot. I admit, such a folding is a mite "impractical". Anyone care to check my figures? $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 hetherwi@math.wisc.edu $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666 $$$ 666Return to Top
In article <01bc026d$054f38a0$267e6bcf@rauhala.tyenet.com>, "Daryl Rauhala"Return to Topwrote: > I am in need of a proof by contradiction that the set of prime numbers is > infinite. > > Starts by assuming that the set of primes is finite and the largest prime > is P. > Let x = P! and let y = x + 1. From here is where I can't get things > straight. > I think we want to find the lowest number that will divide x and also > show that because of our assumprion it also divides x which can't be > possible since x and y are consecuctive integers. This is our > contradiction that show our original assumption is wrong and the set in > infinite. > > > Any help in the details would be appriecated. > Remember that every integer is divisble by a prime. Thus y is divisible by some prime. Think about where it is and what it must divide. Don
Wilbert Dijkhof wrote: > > Martijn Dekker wrote: > > > > pausch@electra.saaf.se (Paul Schlyter) wrote: > > > > :In articleReturn to Top, > > :David Kastrup wrote: > > : > > :> Which is why oo is *not* a real number. All expressions involving > > :> real numbers are either undefined, or equal exactly one real number. > > : > > :You mean expressions like: > > : > > :sqrt(4) = +2 or -2 The notation sqrt(4) means only the principal (positive) square root. When we mean the negative square root, we write -sqrt (4). So sqrt(4) is one number, 2. > > : > > :sqrt(sqrt(16)) = +2, -2, +2i or -2i Since the principal square root of 16 is 4 and the principal square root of 4 is 2, this expression represents one number, 2. > > : > > :arctan(1) = pi/4 + n*pi/2 where n is any integer > > : > > :????? The range of the arctangent function is (-pi/2,pi/2) because that is the largest interval (centered about the origin) where the tangent function is one-to-one, therefore the tangent function can only have an inverse on this restricted domain. True, there are an infinite number of angles whose tangent is 1, but the notation arctan(1) means "The angle between -pi/2 and pi/2 whose tangent is 1." In general, (IMHO) the notation y = arctan x implies y is between -pi/2 and pi/2. ____________________________________________________________ Darrell Ryan e-mail dryan@edge.net personal website http://edge.edge.net/~dryan company website http://www.edge.net/stmc
Will pay more than the original retail price for a Sharp EL-5103 calculator in good working condition. The manual for the calculator is desirable but not necessary. Will consider buying any other small, _programmable_, leatherette-covered Sharp calculator model. Not interested in the EL-506 or other non-programmable models, or in the larger models that use the BASIC language (I have those). -- John Chandler jpc@a.cs.okstate.eduReturn to Top
Gaussian Elimination in this case means solving 3 equations in 3 unknowns. With these linear equations, you may not have to worry about Gauss -- you could just write the functions out and go at it analytically. However, Gaussian elimination is basically an approach whereby you write the 3x3 matrix of the equations, i.e., with the equations in the rows and the variables in the columns: Ax=b where A is the 3x3 matrix of coefficients of the equation x are the 3 variables to be solved for b is a [3,1] vector of the values of the functions when solved. [Qualitative concept] You basically take the first row of A, normalize it so that the top left value in A is 1, then subtract it out of all the lower rows, so that all values in the first column are 0 (except for the top row). Then, you do this for the second row and thrid row. What you then have is a transformed A' where all the values in the lower left are 0. The lowest row is now c*x3=d, so you can solve for x3. Knowing x3, you can also solve the second row for x2 from e*x2 + f*x3=g. Then you can solve for x1 in the first row. [Modifications] Often,the diagonals in A may be 0, which ruins the whole thing. Also, you need to worry about roundoff. So an added feature is "maximum row-column pivoting", where for each forward iteration, instead of normalizing (pivoting) on the diagonal, you find the next largest value in the matrix and pivot on that. Any practical matrix book should explain this (much better than I did). Also, there is lots of code around. For a Fortran code, look at Carnahan, Luther, Wilkes. If you need more help, let me know. I would advise not writing your own code, and there are some subtle things to worry about in coding. However, there is a lot of off-the-shelf code on this.Return to Top
I am a Junior in Highschool taking Alg 2 trig and was wondering if anyone knew of any books that would help me in this class as well as in AP Clac. Thanx in advance.Return to Top
(posted & emailed) Brent HetherwickReturn to Topwrote: > > Keith Pitcher (kpitcher@weirdness.com) wrote: > : Q) Take a square piece of paper. Fold it in half. Do it again. Repeat 25 > : times. How many sheets thick is the final folded piece of paper. > : > : My sister realized that this was a trick question, as she knew a piece > : of paper can > : not be folded that many times in half, and so far every question had > : been based in reality. [...] > > What if the sheet of paper had been 25' x 25'? Or large enough to carry > this out? I assume you mean conceptually, as real paper could not be folded that many times. (To see this, consider the thickness of the thinnest paper commercially available, and consider the number of layers even assuming that the paper were cut in half and piled up, instead of being folded, etc.) How is such an answer related to reality? > Why didn't she ASK the teacher if it was a "trick question"? It sounded as if this was one of a series of questions on a test, and students don't always have the option of asking during a test. (Standardized achievement tests come to mind.) I don't understand how one wrong answer would produce an "F", though, unless most of the rest of the answers were wrong as well. > Why didn't she ASK for clarification of the problem? Doesn't it seem > implausible that an honest teacher would try to trick students with a > problem anyway? My daughter has suffered through a few ignorant or careless teachers, so dishonesty is not the only explanation for a poorly worded question. (Fortunately, we've encountered many excellent teachers as well.) > In any case, trying to must professional opinion on your > side is a very bad idea; at best, it can only serve to falsely enhance > your ego at the expense of good pupil-teacher relations. *What* good pupil-teacher relations? It sounds as if the teacher has already been consulted and is inflexible. Some teachers are like that. If I were the student, I would already have lost most of my respect for this teacher. > The matter truly > is a judgement call, and you're only asking for trouble by trying to "go > over" the teachers head, so to speak, in appealing to a greater > authority. There is risk here, but this statement is asserted without proof. My wife and I complained to the school principal about a fifth-grade teacher's erroneous disqualification of our daughter's answer on an arithmetic problem. The eventual result was that the teacher, the next summer, took an algebra class as part of her professional-enhancement course work and, from what we heard, became a much more effective arithmetic teacher. We derived the satisfaction that other children would not learn false ideas from her that they would later have to unlearn. Unfortunately, there are poor teachers everywhere, but one can learn even from a poor teacher. Part of being a successful student is knowing how to guess what kind of answer the teacher wants. Often, this involves having learned the subject matter, but sometimes other considerations come into play. Some of the game playing that a student must do to be successful is even useful in later life, as when one becomes involved in office politics. Probably the best strategy for answering the "folding" question would have been to say something like, "Assuming that the total number of folds is 26, the number of sheets is..." If the guess at the total number of folds is wrong, at least the student demonstrates an understanding of how to do the calculation, and should get partial credit. To me, the question is ambiguous, and its meaning depends on what is repeated and when the repetition starts. I get total numbers of folds of 1, 25, 26, 27, 50, and 52 (this last assumes that the original 2 folds are followed by 25 more pairs of folds). -- -- Vincent Johns Please feel free to quote anything I say here.
In articleReturn to Top, Jessica T. Fried wrote: > > I'm looking for a topic to write a short paper on for my 300 level >Diff.Eqn. class(undergrad). I'm really interested in plants, and would >love to know if there are any SIMPLE applications of Diff.Eqn. in botany. >If anyone out there has any ideas please drop me a line. If the interest in plants extends to fungi hunt out Buller's "Researches on Fungi" (an old but famous book, several volumes) and see his discussion of the "sporabola" = path followed by a fungus spore when shot off at a low Reynolds number. (It's what a parabola becomes when there's a lot of air resistance.) C T Ingold wrote a couple of later books taking such points up. Then there's W.K. Silk and R.O. Erickson "Kinematics of plant growth" J.Theoret.Biol. 76 481-501, 1979 and P.W.Gandar "The analysis of growth and cell production in root apices" Bot.Gaz. 141(2) 131-138, 1980, and whatever the Science Citation Index leads you to: this isn't my field so I don't know what's been done since. It does involve some simple DEs though. John Harper School of Math+Comp Sci Victoria Univ Wellington New Zealand
Alan \"Uncle Al\" SchwartzReturn to Topwrote in article <5bh392$op8@dfw-ixnews7.ix.netcom.com>... > Leonard Timmons wrote: > >Is the duality between mind and matter equivalent > >to the duality between numbers and numerals? > > The duality between mind and matter is isomorphous to the duality between > fish and bicycles. Is this post designed only for women? > > -- > Alan "Uncle Al" Schwartz > UncleAl0@ix.netcom.com ("zero" before @) > http://www.ultra.net.au/~wisby/uncleal.htm > (Toxic URL! Unsafe for children, Democrats, and most mammals) > "Quis custodiet ipsos custodes?" The Net! > > >
In article <5bgu7h$1m2a@inst.augie.edu>, (Augie) wrote: * "Nathan Crowder"Return to Topwrote: * * >How many real solutions does the equation sin(x)=(x/100) have? X‰15.5, 6.34, 3.11, 0, -3.11, -6.34, -15.5 -- JZS 3=)
In article <5bgu7h$1m2a@inst.augie.edu>, (Augie) wrote: * "Nathan Crowder"Return to Topwrote: * * >How many real solutions does the equation sin(x)=(x/100) have? X‰15.5, 6.34, 3.11, 0, -3.11, -6.34, -15.5 -- JZS 3=)
bm373592@muenchen.org (Uenal Mutlu) writes: >LOTSIM - Simulation-Program for all pick-X type Lottery Games >[text deleted] > Draw numbers are generated by the standard RNG, ie. the rand() > function. Seed (srand(time)) is done once at pgmstart. Is this in C? You should note that the pseudo-random number generator in most implementations of C is flawed. C returns an unsigned integer but the rightmost bits of the number returned are NOT RANDOM! Suppose C returns an integer in the range from 1 through 4,000,000,000 and you want to convert this to a number in the range from 1 through 49. Typically, programmers use the formula x = (n mod 49) + 1 to convert n, the number returned by pseudo-random number generator, to the number x of the desired range. This is a bad thing to do in C. This formula emphasizes the bits on the right end, namely those bits that are not random. To use the C's random number generator properly, you have to first get rid of the rightmost bits. (e.g. x >>= 8 will get rid of the 8 rightmost bits) If you want to do some serious simulations with lots of samples, you really shouldn't use any language's built-in generator and instead use a stronger generator. -- Glenn RhoadsReturn to Top
In article <01bc026d$054f38a0$267e6bcf@rauhala.tyenet.com>, "Daryl Rauhala"Return to Topwrote: > > > I am in need of a proof by contradiction that the set of prime numbers is > infinite. > > Starts by assuming that the set of primes is finite and the largest prime > is P. > Let x = P! and let y = x + 1. From here is where I can't get things > straight. > I think we want to find the lowest number that will divide x and also > show that because of our assumprion it also divides x which can't be > possible since x and y are consecuctive integers. This is our > contradiction that show our original assumption is wrong and the set in > infinite. Strangely enough there has been a long, tedious debate on this forum on just this. One notorious author came up with a new improvement to the usual approach. But he wrongly insists that the usual argument is incorrect while others wrongly insist that his argument is incorrect. Your approach of finding y is valid. (An alternative is to use z = (product of primes <= P) + 1). The next step is to note that y cannot be divided by any number less than or equal to P. As you assumed the only prime numbers are less than or equal to P, this is divisible by no primes so it must be prime. But it's a prime larger than P - contradiciton. If your teacher sides with the cranks who didn't like this argument you may be able to keep the US law courts tied up for a few millenia if you choose to sue. Terry Moore, Statistics Department, Massey University, New Zealand. Imagine a person with a gift of ridicule [He might say] First that a negative quantity has no logarithm; secondly that a negative quantity has no square root; thirdly that the first non-existent is to the second as the circumference of a circle is to the diameter. Augustus de Morgan
In <5bfneu$3v1@nntp1.u.washington.edu> hillman@math.washington.edu (Christopher Hillman) writes: > >In article <32DB0B90.3A6F@quadrant.net>, >"Bruce C. Fielder"Return to Topwrites: > >|> If the gravitation of a black hole is such that anything falling into a >|> black hole will have its "time" slowed the closer it comes to the event >|> horizon, how does the thing form in the first place? Surely as the >|> original mass contracts, it should slow (from our point of view) until >|> the original mass remains "waiting" (sorry about all the quotation >|> marks) at the event horizon? >|> >|> As far as I can see, the same should hold true with the mass inside the >|> (soon to be) event horizon; the acceleration and gravity increases and >|> slows the time to infinity. So how does the thing ever form in our >|> universe? > >The "picture" of a black hole you probably have in mind (really a sort of >map of a particular closed space-time, in the same sense that a Mercator >projection is a particular map of a certain curved surface) are the >Scharwzchild coordinates, in which the "event" horizon appears as >a cylindrical coordinate singularity. Geometrically, this cylinder >(in the map) is really a circle (i.e. a two-sphere). There are other >coordinate systems in which this coordinate singularity is removed. >The best is a conformal map (preserving small shapes, like the Mercator >projection does for the surface of the earth) called the Kruskal-Szekeres >coordinates. > >It is true that an exterior observer (usually assumed to be stationary >wrt to the black hole) observes nothing of the history of a particle >after it passes through the event horizon. Moreover, as a particle >approaches the horizon, signals from it back to more distant observers >are extremely redshifted and also fade in intensity (exponentially in the >time of a distant observer, in fact, contrary to the impression left >by the Schwarzchild coordinates that a distant observer will observe >particles "hanging" suspended near the event horizon. > >Nonetheless, a particle falling into the BH (or the matter of the star >itself as the hole is being formed) experiences nothing strange as it passes >through the event horizon. The event horizon is an artificial mental construction >(like the international date line) which has a GLOBAL significance (this is >the point of no return) but no LOCAL (physical) meaning. Indeed, by >a remarkable coincidence, it turns out that you can obtain the correct >experience according to gtr by a simple Newtonian analysis. Specifically: > >Consider two particles falling straight into a gravitational source of mass M. >Suppose one is at radius R and the other at radius R+L (L small wrt R). >Then they accelerate apart relative to one another as > > -GM/R^2 + GM/(R+L)^2 ~ 2GML/R^3 > >(where we expand in a power series in L, neglecting all but the first order term). >If we have two particles both at radius R and seperated tangentially by L, >they accelerate toward one another as > > -GM/R^2 (L/R) = -GML/R^3 > >(by similar triangles). That is, the curvature coefficients are 2GM/R^3 radially >and -GM/R^2 tangentially. Someone falling into a black hole is therefore >compressed tangentially and expanded radially by the force of gravity, this effect >increasing smoothly as R^(-3) right through the event horizon and down to >the true singularity at R=0. > >It is not obvious but true that these Newtonian values are in fact correct >according to standard gtr for a non-rotating non-charged black hole. >I have modeled this discussion on the first few pages of the beautiful >book Gravitation, by Misner, Thorne, and Wheeler, Freeman 1970, which >also contains a thorough discussion of many coordinate systems for >black holes including the Kruskal-Szekeres coordinates, and various >techniques for calculating the curvatures and verifying that the values >given here are correct. > >Another way to visualize the situation is to consider a sphere of particles >"at infinity". They begin to fall slowly into the hole, carving a three >dimensional surface out in the four dimensional space-time as they do so. >You can readily determine the intrinsic geometry of this section using >methods dicussed in MTW and then it turns out you can embedd this "world-surface" >as a sort of half-football in R^4. Again, the event horizon is simply one of many >spherical "latitude surfaces" on this football, and is not distinguished in any >way from its brethern. Incidently, such "world surfaces" form an entire family >of surfaces carving up the space time. There is a family of "orthogonal" surfaces >defined in the same way that potential curves determine streamlines in the >conformal mapping method of solving hydrodynamical flow problems. These >orthogonal surfaces are flat R^3 planes, flat right down to the singularity! >That is, the Scharzchild universe is a sort of four dimensonal "ruled surface". >A more familiar example of a (two dimensional) ruled surface is obtained by >taking a twisting curve in R^3 and considering the surface carved out by its >tangents. Typically this surface has a sharp cusp along the curve itself; >the true singularity as the center of a black hole arises geometrically >in an analogous fashion. > >Hope this helps! > >Chris Hillman Mr. Hillman, you explained in another post that mass and kinetic energy both contribute to the mass-energy of a particle. A body is therefore its total mass-energy. You stated in another post that the velocity space of a body is a Lobachevsky geometry. Mr. Archimedes Plutonium has stated that the Lobachevsky geometry does not have a zero reference point. Since a body with constant velocity has a non-zero slope in the Loba geometry, it therefore has a potential energy? The start metric of the potential energy can then be calculated because the Loba geometry does not have a zero reference point? Could the relation between the potential energy and inertial energy be the same as the relation between the electric and magnetic fields? The potential field induces an inertial field and the inertial field induces a potential field: potential flux thereby inducing inertial flux? Since a body is nothing but the mass-energy given by the sum of mass and kinetic energy, then the motion of a macroscopic body is therefore the potential-inertial propagation of the mass? Regards, Edward Meisner
In <5bc184$q32$1@dartvax.dartmouth.edu> Archimedes.Plutonium@dartmouth.edu (Archimedes Plutonium) writes: > > If the US had been a parliamentary form of government where all >politicians are elected and not these cabinets that linger from one >administration to another and really run the government. Then, >hypothetically, is it highly likely that the Vietnam War would have >never occurred? Or if it had, would not a parliamentary form of >government gotten the US out quicker? One can argue that the US Vietnam >War was chiefly the result of foolish advisors to the president. > > Perhaps this is a great research inquiry as to see which form of >democracy is superior-- the US or the UK parliamentary. > > In a parliamentary system, the likelihood of foolish advisors doing >so much damage is minimized, I suspect. > > Same thing in mathematics, where math is run by the old geezers who >control the math journals. They print and publish the pipsqueak little >progress. And they do their utmost best to keep out anything that is >big, new and exciting and important. In fact, they mostly publish that >which furthers their own self interests or >you-rub-my-hand-I-rub-your-hand. > > The clowns that got the US into Vietnam are the same sort of >intellectual clowns that control the mathematics publishing journals >and who hate an idea such as Naturals = P-adics = Infinite Integers. Although the Democrats bear the ultimate responsibility for bogging the US down in Vietnam, they did so in no small part to avoid looking "soft" in the face of Republican criticism; Republicans were inclined to hold a harder line. I;m not sure this dynamic would have been any different under a parliamentary system. - CMCReturn to Top
Rodney HunsickerReturn to Topwrote: >Ward Stewart wrote: >> We debate it because these odd folks, supposing that their >> ommnipotent deity is too lame to manage his own vinyard have >> decided that THEY must do the weeding. THEY have the power >> to determine who has been anughty and who has been nice. >> >> THEY are on thin ice, theologically and morally and had best >> watch their step. >> >> ward >> >God made light. By it we see. Without it we cannot focus are attention >on externals. God made the world. We see it in light. >An infinite multitude of world exists in darkness and we see only what >the flashlight of our preception can capture momentarily. Math is a >vain attempt to place order on that which is already ordered. God is >said to be within. God cannot be seen in the light because he is not in >the darkness. God is known through faith, and faith is grown in love. >Love is the only "light" that can reveal the existance of God. This is a classic example of plain old-fashioned FLAPDOODLE! ward ******************************************************* "The Bible contains six admonishments to homosexuals and three hundred sixty two admonishments to heterosexuals. That doesn't mean that God doesn't love heterosexuals. It's just that they need more supervision." -Lynne Lavner
Allen Adler wrote: > > In 1965, Oxford University Press published an english > translation of S.G.Mikhlin's book "Multidimensional > singular integrals and integral equations". There is a newer book by Mikhlin and Proessdorf, Singular Integral Operators. I don't know the exact data of the english translation. The german version is Akademie-Verlag Berlin, 1980. Uwe KaehlerReturn to Top
Dear Richard, On December 26, 1996, you had asked, "how many unlabeled trees are there on n vertices where the valency of each vertex is ... the case v=4. ... in more chemical terms, how many isomers of an n-alkane are there?" I had replied earlier to comment that real-life carbon chemistry doesn't match the mathematics of unlabeled trees too well. Tonight in the library I encountered _Combinatorial Enumeration of Groups, Graphs and Chemical Compounds_ by Polya and Read, Springer-Verlag (1987). I had no time to look for your answer, but suspect that this source covers much of what is known. Patrick T. Wahl ( no institutional affiliation )Return to Top
I found out from a web site that there was a Biography on Martin Gardner some time in 1996. Being a huge fan of his work and also of David Suzuki, who did the documentary, I would be greatly indebted to any kind sole who could share a copy of this episode. Norm Heske http://www.westworld.com/~heskeReturn to Top
-----BEGIN PGP SIGNED MESSAGE----- These articles appeared to be off-topic to the 'bot, who posts these notices as a convenience to the Usenet readers, who may choose to mark these articles as "already read". You can find the software to process these notices with some newsreaders at CancelMoose's[tm] WWW site: http://www.cm.org. Poster breakdown, culled from the From: headers, with byte counts: 1 1810 Archimedes.Plutonium@dartmouth.edu (Archimedes Plutonium) The 'bot does not e-mail these posters and is not affiliated with the several people who choose to do so. @@BEGIN NCM HEADERS Version: 0.93 Issuer: sci.math-NoCeMbot@bwalk.dm.com Type: off-topic Newsgroup: sci.math Action: hide Count: 1 Notice-ID: smncm1997014061434 @@BEGIN NCM BODY <5bh3oc$ttp$1@dartvax.dartmouth.edu> sci.math @@END NCM BODY Feel free to e-mail the 'bot for a copy of its PGP public key or to comment on its criteria for finding off-topic articles. All e-mail will be read by humans. -----BEGIN PGP SIGNATURE----- Version: 2.6 iQCVAwUBMtx1zDLKBVWUZJPVAQEdWwP/Ux4Tb8BzGPOZTn0Kbq4bJo0riAJBbaoC 4u/a+21qV+ufBlaqHA/6FMbCYLAgOSG6G2SY00MtfzjXz3MlhNXqoMdXAlpiVxuT IyKcAUutWs9Zcz7Oim6GoPup1c/RXnbrTd7gpYM2U8T3W4wJ8D8rAN0LtJ7gehQq z9atregzGqM= =WH8V -----END PGP SIGNATURE-----Return to Top
On January 8, Monte J. Zerger asked, "With all this focus on the coming millenium, I am curious what we will call the year 10,000. ... What about ... 100,000 years?" This adds to my January 13 posting on the topic of words for the "deka-millenium" or whatever. I spent a little time in the library tonight with the big dictionaries in Latin, Greek and English (O.E.D.) I'm not going to try to write in Greek. My transliterations here map the "x" or "chi" letter to "ch" and both "epsilon" and "eta" to "e." Please forgive my ignorance of classic grammar; perhaps someone more educated can get the declensions right. Classical Greek seems to be the best source. My earlier guess at the word is wrong. The Greek word "myrioi" for 10,000 is the source of "myrietes" and "myrieteris," which mean "a period of 10,000 years." Similarly, there is "chilieteris," a period of 1,000 years, which uses the "chili-" prefix that became our "kilo-." By the way, there's a very long word for a myriad of myriads = 10^8 in Greek. Nothing like these spellings seems to have entered English. Classical Latin seems to have had a wealth of "-ennium" words, including some that I didn't suspect ( like triennium, tricennium, tricentennium for periods of 3, 30 and 300 years respectively.) The word "millenium" is the biggest I found. It appears that a modifier got stuck on the front if there was more than a thousand of anything. Something like "decei millenii" for ten millenia seems to be what they used. Consulting the Oxford English Dictionary, I found no word for "10,000 years" that survived into English. ( Particularly NOT "myriennium" or "myriayore": those are not in the O.E.D. ) I was surprised to find the Greek "chili-" word above as the English word "chiliad." It means "a group of 1000," but also "1000 years." Might "myriad" have the alternate meaning, too? Only a scholar can say, and the O.E.D. gave no citation for such a use. In short, one had best look to Hindi/Sanskrit/Indo-European Ursprache. If English ever had the word we seek, it seems to have been forgotten. But if all else fails, my vote goes to "myriad." Pedantically yours, Patrick T. Wahl ( no institutional affiliation )Return to Top
In article <32DB9FDA.71E7@mindspring.com>, R M MentockReturn to Topwrote: > > rjc@maths.ex.ac.uk wrote: > > > I can show non-existence for n = 3, 4, 7, 8, 11, 12 etc. as follows. > > Very nice! but shouldn't that be "non-existence for 1,2,5,6,9,10 etc.", > instead? > Errrr yeah, of course :-) Robin -------------------==== Posted via Deja News ====----------------------- http://www.dejanews.com/ Search, Read, Post to Usenet
In article <5bh4ud$oe9@geraldo.cc.utexas.edu>, mlerma@math.utexas.edu (Miguel Lerma) writes: |> Christopher Hillman (hillman@math.washington.edu) wrote: |> [...] |> > Nonetheless, a particle falling into the BH (or the matter of the star |> > itself as the hole is being formed) experiences nothing strange as it passes |> > through the event horizon. The event horizon is an artificial mental construction |> |> Let me ask a follow up question. In Schwarchild's coordinates the |> particle passes through the event horizon at time t = infinity. |> However, Hawking has shown that a black hole cannot last until |> t = infinity, it will evaporate first. If by the time the particle |> enters the black hole it does not exist any more, how can it do it? |> Someone told me that the "paradox" comes from an improper mixture of |> classical and quantum physics, I would agree with that, as far as it goes. Another way of putting this would be to guess that Schwarchild coordinates are inappropriate for analyzing events near the horizon, because of the coordinate singularity there. |> but I would appreciate any more detailed |> explanation about how matter can fall inside an evaporating (non rotating |> and non charged) black hole. Sorry, can't help you there. I have a good geometric understanding of the purely classical theory (attained through self study of Misner-Thorne-Wheeler), but I cannot claim to know much about quantum mechanics in general or Hawking's work in particular. Hopefully someone who is familar with Hawking's computations will be tempted to attempt an answer to your question. Chris HillmanReturn to Top
Michael A. Stueben wrote: > > Not only can I give you a short easy-to-understand proof of the > existence of God. I can do better I can prove to you that I am > God. > > PROOF: Everytime I find myself talking to God, I realize that I > am only talking to myself. Q.E.D. Really? And every time you have sex with a woman you find that it was only with yourself? Q.E.D. > > COMMENT: The existence of God is independent of the question is > God the Christian God? There is only one God, he's made it quite plain (the God of Abraham, Isaac, Jacob, ect...). > > CONVERSATION: I believe in God. Why do you believe your belief > is correct? I believe my belief is correct. Well then, why do > you believe your belief of your belief is correct? I believe my > belief of my belief is correct. well why do you believe your > belief of your belief of your belief is correct? i believe my > belief . . . > > The above conversation is nuts. I agree, quit talking with yourself. The bible gives quite a few predictions that have and others are about to come true. Why waste time talking with yourself? Go to the source, read the bible. Start with the chapter of Matthew, ask Jesus to forgive your sins and quit worring about the trivial garbage above. Jesus's forgiveness is FREE, you only have to ask for it, or don't. Best of luck.Return to Top
Daryl Rauhala (rauhala@tyenet.com) wrote: : : I am in need of a proof by contradiction that the set of prime numbers is : infinite. : : Starts by assuming that the set of primes is finite and the largest prime : is P. : Let x = P! and let y = x + 1. From here is where I can't get things : straight. : I think we want to find the lowest number that will divide x and also : show that because of our assumprion it also divides x which can't be : possible since x and y are consecuctive integers. This is our : contradiction that show our original assumption is wrong and the set in : infinite. : : : Any help in the details would be appriecated. : : Daryl : Lively,Ontario Ok, assume the set of primes is finite. Then you can multiply all the primes and add one. This number is not divisible by any prime according to our hypothesis, but since it's greater than any prime, also according to our hypothesis - it must be divisible by some prime. Contradiction. -Dave D.Return to Top
Leonard Timmons (ltimmons@mindspring.com) wrote: : Alan "Uncle Al" Schwartz wrote: : > : > Leonard TimmonsReturn to Topwrote: : > >Is the duality between mind and matter equivalent : > >to the duality between numbers and numerals? : > : > The duality between mind and matter is isomorphous to the duality between : > fish and bicycles. : : Hey, I think you are making fun of me. Someday, when I start taking myself : seriously, I'm going to be upset. ;-) : : In the mean time, though ... : : Does anyone out there believe that numbers (not numerals) actually : exist (what ever that means) and on what basis are you making that : claim? : : My second question: Does anyone out there believe that numerals : actually exist and on what basis are you making that claim? : : Go ahead, make fun of me. I can take it. I would say he's spoking fun at you. But you have to expect this if you ask metafishical questions. At least you didn't fall for it hook line and sinker. If you mean to be serious, I would say first that numerals are just notation for numbers and are therefore social constructs. Numbers, however, have a significance beyond social convention. Pi, I believe will be discovered by intelligent life where ever and whenever it arises. Matter and reality inhabit the space of abstract logical possibility. The most elementary and accessible parts of this space are known to us as mathematics. -Dave D.
I am looking for some fresh ideas or lesson plans for projects using the scientific method. Subjects that are of interest include, math, social studies, language arts, foreign language, ect... Grade 6-8 Please E-mail responsesReturn to Top
The folowing three references should give you all you need. DIVERGENT SERIES, HARDY,CHELSEA PUB. CO. INFINITE SERIES, BROMWICH,CHELSEA THEORY AND APPLICATION OF INFINITE SERIES,KNOPP,BLACKIE&SON; LTD. (ALSO AVAILABLE FROM DOVER IN PAPER BACK) Tom Robbins (TRobb10244@aol.com)Return to Top
In article <5bhpbg$hfq@dfw-ixnews9.ix.netcom.com>, odessey2@ix.netcom.com (Allen Meisner) writes: |> Mr. Hillman, you explained in another post that mass and kinetic |> energy both contribute to the mass-energy of a particle. Yes, the total energy (expanded in a power series in v) is m/Sqrt{1-v^2} ~ m + (1/2) m v^2 + (3/8) m v^4 + ... where the first term is the mass, the second term is the Newtonian value for the kinetic energy, and the remaining terms may be considered relativistic corrections to the kinetic energy (which are important only for values of v close to 1). |> You stated in another post that the |> velocity space of a body is a Lobachevsky geometry. Yes, The velocity space is space of forward pointing unit vectors, which can act as tangent vectors to world lines; the spacelike components of such vectors are interpreted as the components of the velocity and the timelike component gives the time dilation rate at that event (for a clock carried with the particle, relative to the rest frame). |> Mr. Archimedes |> Plutonium has stated that the Lobachevsky geometry does not have a zero |> reference point. In the same sense that ordinary euclidean space does not have any distinguished points, he is correct. The euclidean plane, the ordinary sphere, the Lobachevsky "hyperbolic" space (topologically a plane and thus often called "the hyperbolic plane") and the velocity space of tachyons (topologically a cylinder) are all surfaces of constant curvature and thus have no geometrically distinguished points. Thus, the choice of an origin for any coordinate system is arbitrary. The euclidean plane has constant curvature zero, and can be given the familiar Cartesian coordinates. The remaining surfaces have constant nonzero curvature and cannot be given a Cartesian coordinate system; in fact, the sphere cannot be given ANY global coordinate system (i.e. one which avoids coordinate singularities at all points) whereas the others can be given global, nicely behaved conformal coordinate systems. One popular conformal system for the Lobachevsky space was introduced by Poincare and maps this space onto a disk of unit radius (with the geodesics represented as circular arcs whose ends are orthogonal to the bounding circle). A good conformal system for the tachyon velocity space is the exact analog of the Mercator projection for the sphere (it represents lightlike geodesics as straight line segments). |> Since a body with constant velocity has a non-zero slope in the Loba geometry, Unfortunately present technology does not support the drawing of a freehand picture or two which would have greatly clarified my posting discussing velocity spaces. In fact, a body with constant velocity (i.e. whose world line has a constant unit tangent vector all along the world line) is represented in the velocity space by a POINT. On the other hand, a body with a curved world line experiences accelerations and such a world line corresponds in the velocity space to a curve; in the case of constant acceleration this curve is a geodesic (topologically a line) on the Lobachevsky space. "Velocity space" is called that because its POINTS correspond to possible values for the velocity associated with a particular event on a given body's world line. What you wrote after the quoted remark seemed pretty far off the mark to me--- possibly because of the misunderstanding just noted. Chris HillmanReturn to Top
jac@ibms46.scri.fsu.edu (Jim Carr) wrote: | davk@netcom.com (David Kaufman) writes: | > | >The square root of 2 can be written in Basic computer language | >as follows: 2^.5 or 2^(1/2) or SQR(2). | ======= | | If this is valid Basic, no wonder it is commonly said that those | who learn Basic first are often crippled for life as programmers. | That expression is equal to 1 in other high-level languages. Pursuant to Eric's clever observation about the literal use of this pseudo-Tex expression in C, it was always my intent that one first express it in the usual way of doing exponentiation. And, of course, the main reason BASIC does not even make the top 8 of "first languages" used for CS teaching is more due to its discouragement of structured programming methods than any differences in how it interprets arithmetic statements. Actually, I don't know what it does, but I can spot BASIC written in C (only global variables!) in my student's code from 10 paces away. Simon ReadReturn to Topwrites: > >rubbish nonsense rubbish nonsense drivel nonsense garbage >spew bilge tosh tripe rhubarb moonshine nonsense hogwash > >2^(1/2) is the square root of two unless you deliberately do >something strange, like using integer variables. But that is exactly what the original author did, using a real constant (0.5) in the first formula and an integer expression (1/2) in the second. I will add that it is not unusual for semi- experienced programmers (CS majors, after the C++ course) to make the mistake of directly transcribing the printed equation that results from that TeX expression into code that uses 1/2 = 0 as the exponent in the pow function. More than half, usually. >There are some finer points of FORTRAN where you can ask for integers, >or possibly get things evaluated as integers >_by not using any decimal points_ Of course, decimal points were not used in the above statements, but my reason for this response is the reference to Fortran, an urban legend that might explain why students who write in C might think they are immune to it. They are not. Ditto for Ada, altough the strong-typing might make you notice what you were doing. >No way does BASIC cause people to be crippled for life as programmers. >BASIC bears a strong resemblance to FORTRAN and Pascal, as a matter >of fact, There are modern versions of it that have logical structures, independent subprogram modules with private data, etc, but the original language is an abomination. >It was invented as a teaching tool. Pascal was invented as a teaching tool. BASIC was invented so you could write very crude programs on exceedingly primitive computers, AFAIK. If it was invented as a teaching tool, who is guilty? -- James A. Carr | "The half of knowledge is knowing http://www.scri.fsu.edu/~jac/ | where to find knowledge" - Anon. Supercomputer Computations Res. Inst. | Motto over the entrance to Dodd Florida State, Tallahassee FL 32306 | Hall, former library at FSCW.
In <5belj4$2ng$1@nuke.csu.net>, ikastan@sol.uucp (ilias kastanas 08-14-90) writes: > I just see no reason for empty domains Consider the classic example of an empty domains -- quantification over the set of all Unicorns. Sounds good, except that Unicorns *do* exist (modified goat stock, I believe), and with genetic engineering *might* exist in the future (in other forms). The problem with assuming non-empty domains, is that frequently one is unaware of the fact that the domain is empty. Or perhaps cannot even know if the domain is empty -- how about sets whose defining predicates require the solution of something like the 4-color map problem? Or the domain may be empty today, but not tomorrow. Or perhaps the reverse. Reasoning should be correct *regardless* of the cardinality of the set being reasoned about. If the reasoning is correct, it is correct regardless if the set is later found to contain one element or none. But classical logic only allows discussion of non-empty domains. So, much of actual mathematical practice is therefore unjustified from the standpoint of the underlying logic. This is clearly unacceptable.Return to Top
In article <32DBBDEB.42415D54@alcyone.com>, Erik Max FrancisReturn to Topwrites: |> Peter Diehr wrote: |> |> > > Black Holes in the GR sense remain hypothetical. |> > |> > You haven't been following the news very closely, have you? |> |> There is still no positive, undeniable evidence that a black hole exists. |> I think it's safe to say that most physicists are pretty sure there exist, |> an we have some convincing candidates, but there isn't quite the degree of |> certainty yet that would warrant your objection. By coincidence Ramesh Narayan (Harvard-Smithsonian Center for Astrophysics) has just announced the apparent direct observation of hot gas disappearing into the event horizon of a black hole (one member of the double star V404Cyg in the constellation Cygnus, only 10,000 light years from Earth.) Apparently their observations confirm a recent theoretical prediction that gas being sucked into a hole can become superheated. Narayan said that object "seems to be swallowing nearly a hundred times as much energy as it radiates". In comparison, in the case of several other double stars his team studied, hot gas was observed flashing as it impacted the surface of a dense object interpreted as a neutron star. Furthermore, Douglas Richstone (University of Michigan) just announced the discovery of three new supercompact dark objects (presumably black holes) with masses in the range 50-500 x 10^6 solar masses. These objects were detected by their violent gravitational effects on nearby stars, and they are all within 50 million light years of the Earth. So evidence continues to accumulate that black holes not only exist but are quite common. Chris Hillman
Cyberman (cyberman@zerocity.it) wrote: > Hello. I've a little problem: > I must invert this function: y = (x^2) + x for x >= 0 > Is there anybody that could help me? You want to solve for x... a quadratic: x^2+x-y=0, x=(-1+SQRT(1+4y))/2 (plus in the square root since x>0) So, the inverse function of f(x)=x^2+x is f^(-1)(y)=(-1+SQRT(1+4y))/2 [or f^(-1)(x)=(-1+SQRT(1+4x))/2]Return to Top
kfoster@rainbow.rmii.com (Kurt Foster) writes: > : And if you shift right the letters HAL you will get his dady's name. > : > "Hal (for *H*euristically programmed *AL*gorithmic computer, no less) > was a masterwork of the third computer breakthrough. ..." -- "2001 a space > odyssey" -- a novel by Arthur C. Clarke > The fact that shifting ther letters by 1 gives "IBM" is simply a > coincidence. Arthur C. Clarke says so. And do *you* seriously believe Clarke in this question? -- Jon Haugsand Dept. of Informatics, Univ. of Oslo, Norway, mailto:jonhaug@ifi.uio.no http://www.ifi.uio.no/~jonhaug/, Pho/fax: +47-22852441/+47-22852401Return to Top
andrew harford (cs4-03@cslan.ud.ie) wrote: > Does anyone know if the following is true? > If A is a connected subset of a real vector > space then for any elements x,y in A, there > exists a continuous function f:[0,1]->A so > that f(x)=0 and f(1)=y (using the usual > topology). No. In the plane the standard counter example is the topologist's sine curve (y=sin(1/x) for x>0) along with the point (0,0). It is not path connected The point (0,0) cannot be connected to a point on the sine curve by a continuous function (for if x=g(t),y=h(t) is a continuous function connecting (0,0) to some point (a,sin(1/a) then consider just x=g(t) with g(0)=0, g(1)=a... there exists a sequence t_j->t_0 (decreasing sequence) with g(t_0)=0 (zero may not be the only value of t for which g(t)=0!) and g(t_j)>0 and h(t_j)=1 (let x_j=1/(pi/2 + 2*j*pi) which decreases to zero... for j>some J, x_j are smaller than a and by the intermediate value theorem, there is a t_J<1 with g(t_J)=x_J. Again, by the intermediate value theorem, there is a t_(J+1)0}, h(t_j) must lie on the curve, so h(t_j)=sin(x_j)=1. But then lim(h(t_j))=1 while h(t_0)=0, so h cannot be continuous... viz. there cannot be a continuous function in this set mapping (0,0) to another point) It is connected If E,F are disjoint relatively open sets (relative to the topologist's sine curve plus the origin) of A whose union is A (=top. sine curve plus the origin) which separate A (vis. they are disjoint and their union is A) then... the origin is in one of them, say, E. E must contain an open square containing the origin intersected with A. Thus it must contain some point on the topologist's sine curve as well. Just restricting to the topologist's sine curve (F does not contain the origin and so is contained just in the sine curve) E intersect the sine curve and F intersect the sine curve would disconnect it (unless F is the null set), but that curve is a path (connected!) so F is the null set (since it cannot contain the origin since it is disjoint from E). So.. writing A as the union of disjoint relatively open sets is only possible if one of them is the null set... or A is connected. Thus.. A is connected but not path connected. On the other hand, if A is *open* and connected in a locally path connected space, then it IS path connected. not true for CLOSED sets... (replace A by {(0,y::-1<=y<=1}UNION{(x,y):y=sin(1/x) for x>0}, viz. the topologist's sine curve along with the vertical line segment of length 2 centered at the origin... now the set is closed and connected in this case we would show two sequences, t_j and v_j, interleaved with t_(j+1) Return to Top
Downloaded by WWW Programs
Byron Palmer