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Hi, I am a senior undergraduate student here in Hawaii majoring in Mathematics. If I went on to a graduate school my interest would be in studying sport (football of 2-3 codes in particular) from a statistical viewpoint to predict team performance, player statistics, rate performances, and provide other information. I have seen some papers that have looked at this in some old journals of the American Statistical Association. I have some questions that hopefully some people can provide some insight into or tips or pointers on where to go to find out. My questions are :- 1) Is this a feasible area of research? I have been working on it in a basic way given my own limited resources and time for the past few years. 2) Following from 1) is that at all useful, employment-wise do you think? Are professional teams or others interested in this sort of information? I have had an article or two published in fantasy football magazines, which is basically all about player performance prediction, so a long-term study such as is done in the baseball field would be interesting, I think. 3) What are the best programs? 4) What programs might have people interested in the above type of research? Operations Research as well, perhaps? Other areas? 5) Anything else you might like to add to enlighten a newbie would be great. Thanks, Richard Richard Scott (rscott@hawaii.edu)Return to Top
Here's one: Simplify (x-a)(x-b)(x-c)...(x-z) as much as possible. Lowest number of ASCII characters wins (less than ten is possible). Those of you who have seen it before, or immediately sees the optimal answer, might wait a day or so before replying, so we can get some creativity here :-) olemReturn to Top
In article <32DBBFCC.5532@cfer.ualberta.ca>, Paul SkoczylasReturn to Topwrote: >I have a bunch of small (4-10 points) data sets (x vs y), gathered from >experimental data. All can be very accurately approximated by a cubic. >However, the curvature of the lines vary--some are very linear. What I >need is an accurate measure of the curvature of the lines, so I can >compare them to each other. (What I want to do is see if any other >external variables effect the curvature of the x-y plot.) Try the quantity that is used to minimize in a fancy definition of cubic splines: an approximation of the square root of the integral of the square of the second derivative of the function. (Since the data are near-cubic, this should be quick - use simple Simpson's Rule on the square of the second derivative.) Cheers, ZVK (Slavek).
mfinney@lynchburg.net writes: >But classical logic only allows discussion of non-empty domains. Aristotelian logic, perhaps. But there is no problem with discussing possibly empty domains in ordinary predicate logic, at the cost of introducing a predicate symbol.Return to Top
Hi, I am a computer scientist and working on inductive generalization of structured objects, that can be represented by directed, coloured graph or hypergraphs or conjunctions of logical literals. I am looking for 1. a good, exact and general maximum clique algorithm. 2. a good, exact and general algorithm for matching two directed, coloured graphs or hypergraphs. I am aware of the fact that both problems are NP complete. But perhaps there is a general algorithm that works well for "almost all" graphs or at least many graphs with a property that is not too restrictive. My graphs tend to be rather large but are not symmetrical or regular. They are not planar but are sparsely connected. Tanks for any hint, Peter Geibel -- ==================================== TU Berlin, FG KI, Sekr. FR 5-8 Peter Geibel =================== Franklinstr. 28/29, D-10587 Berlin ============================================= Tel. +49-30-314-25491 ============================ URL http://www.cs.tu-berlin.de/~geibelReturn to Top
davis_d@spcunb.spc.edu (David K. Davis) wrote: >Pi, I believe will be discovered by intelligent life where ever and whenever it arises. No. Intelligent life will discover 6.283193... or 2pi. -- Ray Tomes -- rtomes@kcbbs.gen.nz -- Harmonics Theory -- http://www.vive.com/connect/universe/rt-home.htm http://www.kcbbs.gen.nz/users/rtomes/rt-home.htmReturn to Top
Does this experience sound familiar to you? (pointless example following) I'm a chess problem composer, and I sometimes do it even in my dream. Too bad that when I awake, my problem is cooked and nothing works. So: Did you ever dreamt up some nobel-prize worthy theory, just to realize after awakening that it violates five conservation laws and the data too? -- Hauke Reddmann <:-EX8 fc3a501@math.uni-hamburg.de PRIVATE EMAIL fc3a501@rzaixsrv1.rrz.uni-hamburg.de BACKUP reddmann@chemie.uni-hamburg.de SCIENCE ONLYReturn to Top
>Mike Housky (mike@webworldinc.com) wrote: >[...] >> > Q: "Some of the factors of a locker number are 2, 5, and 9. If it >> > has exactly nine additional factors, what is the locker number?" >> > >> > Answer Given: 90 >> > >> > My Answer: There does not exist a number with this property. > >The divisors of 90 are exactly 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90. >They are 12 in total, so nine more than the three ones shown. The answer >is unique because the number should be a multiple of 2*5*9 = 90, but >any number of the form 90n with n > 1 has more that 12 divisors. The number of factors can be calculated by multiplying the exponent of prime factors plus one. For example, 90 can be written as 2*3^2*5 and the number of factors is (1+1)(2+1)(1+1)=12. Therefore the number of factors <-> product of the exponents. If the product of the exponent is 12, then the number has 12 factors. In this case, 9 must be a factor, so 3 has to have an exponent of 2 or higher. The smallest number we can get that way is 90.Return to Top
Scott Phung wrote:Return to Top> One Final Question for all, > > "Was my answer correct with regards to what the question asked?" > > The original question was, (taken from November 1996 issue of NCTM, > Question 14 on the calendar problems) > > Q: "Some of the factors of a locker number are 2, 5, and 9. If it > has exactly nine additional factors, what is the locker number?" > > Answer Given: 90 > > My Answer: There does not exist a number with this property. I missed most of this thread. The question, as posed, may have problems but your answer is clearly wrong. There does exist at least one common interpretation of the terms "number" and "factor" such that the property holds. Beware of sweeping generalizations. An important part of the study of mathematics is learning the language used by mathematicians. Maybe that should be "languages"--terminology and notation vary. Here's one bit that's fairly common, though: The unqualified use of the term "number" (especially where integers are implied) generally means "natural number". A "factor" usually means a divisor that is not only positive, but also greater than 1. All generalizations are false, Mike.
Archimedes Plutonium wrote: > Thanks but no thanks. In math as in life, it is best to stick to main > essentials and not be sidetracked with tourist curios knick knacks. Adeles and ideles are *not* "tourist curios knick knacks". They play an essential role in number theory, but also in the geometry of algebraic curves (number fields and function fields have a lot in common). They are used extensively in the so-called "class field theory". And, needless to say, they are a central tool in Andrew Wiles proof of Fermat's Theorem (I'm saying this to annoy you, of course). David A. Madore (david.madore@ens.fr, http://www.eleves.ens.fr:8080/home/madore/index.html.en)Return to Top
Hi How do I solve this polynomial equation: y=2X^3+6X+4 What is the method for solving polynoms in an high degree? Thanks Boaz Tel AvivReturn to Top
P} forh}nd takk (Thanks in advance) :) -- * Hans Kr. Ruud The noble art * * Kristine Bonnevies vei 15 of losing face * * 0592 ÅRVOLL may one day save * * Tlf. 22 65 22 34 (hjemme) 22 77 05 35 (jobb) the human race *Return to Top
Mike Housky (mike@webworldinc.com) wrote: [...] > > Q: "Some of the factors of a locker number are 2, 5, and 9. If it > > has exactly nine additional factors, what is the locker number?" > > > > Answer Given: 90 > > > > My Answer: There does not exist a number with this property. The divisors of 90 are exactly 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90. They are 12 in total, so nine more than the three ones shown. The answer is unique because the number should be a multiple of 2*5*9 = 90, but any number of the form 90n with n > 1 has more that 12 divisors. Miguel A. LermaReturn to Top
I'm very interested, too. I'm in Seoul, Korea, though. I'm 15 years old, sophomore and also very good at math and science. I'm not good at HTML or things like that but am really interested and I think I can pick it up pretty quickly. Please give me some information on it. Visit my homepage at http://www.geocities.com/CapeCanaveral/6270/ and download my program. Please remind that my e-mail address is dankang@nuri.net not dan.kang@nuri.net. spectrumReturn to Topwrote > > So email me if you are interested and please include your location of > residence (City, State, Country will be fine), your interests, your > computer abilities (i..e programming or HTML or 3D graphics or CGI or > photoshop or whatever) and ideas with this contest that could help us > fund an education to CalTech ;) -- ><><><><><><><><><><><><><><><><><><><><><><>< Daniel B. Kang - A 10th grader at SIS (Seoul International School) who's interested in getting into Caltech prior to graduation (after the junior year). If you have any info on it, please e-mail me at dankang@nuri.net. <><><><><><><><><><><><><><><><><><><><><><><> My return address is intentionally invalid due to an increasing number of unwanted junk mails. Please take out a period between dan and kang. Thanks. ><><><><><><><><><><><><><><><><><><><><><><><
In article <32dbcf78.1098335@tar-news.tpgi.com.au>, stan francuzReturn to Topwrote: >would appreciate help with this MI question . > >Consider the Fibonnaci sequence 1,1,2,3,5,8,.... > >which may be defined as t(1) = t(2) = 1 , > > and t(n+2) = t(n+1) + t(n) > >Prove by MI > >t(2n) = t(n){t(n+1) +t(n-1)} > > stan From many possible proofs, I choose the one that needs extra work to remove symptoms of outside help: Use 2x2 matrices T(n) = [t(n-1) t(n) ] [t(n) t(n+1)] and to start, define T(0)=I, t(0)=0. (Notice that t(0)=1 fits into the definition of t(n), extended to n=0 by the same formula.) Then induction shows that T(n+1)=T(1)*T(n), so that T(n)=(T(1))^n. By properties of powers, we find that T(2*n) = T(n) * T(n), and then write the last equation in coordinates. As a bonus, you also obtain a shortcut formula for t(n)^2 + t(n+1)^2. Good luck, ZVK (Slavek).
In article <5b3f3c$5qs@news.fsu.edu>, Jim CarrReturn to Topwrote: > Pascal was invented as a teaching tool. BASIC was invented so you > could write very crude programs on exceedingly primitive computers, > AFAIK. If it was invented as a teaching tool, who is guilty? I have read that the original purpose of BASIC was to teach beginning programming students about concepts of assembly language, hence the line numbers, the global namespace, and the lack of structured programming concepts. -- Dave Seaman dseaman@purdue.edu ++++ stop the execution of Mumia Abu-Jamal ++++ ++++ if you agree copy these lines to your sig ++++ ++++ see http://www.xs4all.nl/~tank/spg-l/sigaction.htm ++++
In article <5bc75q$1kj@news.usit.net>, Heath David hart heath@homemail.com says... >macchi@marina.scn.de (Gian Carlo Macchi) wrote: >>I've not followed this thread until now. Anyway, in your example, Roman >>I always counts 1, independently of its position, and X always counts >>10. >>That is why this numbering system is not positional. >I think it could reasonably be argued that in 'VI' the symbol 'I' has >a value of 1, but in 'IV' the symbol 'I' has a value of -1. Negative numbers do not apply to Roman numbering system. So the I in IV can be seen as the number 1 that has to be subtracted to V; so we can say that IV corresponds to 4, i.e. 5 - 1, where the minus is an operator applied to the couple of numbers 5 and 1, not the sign of the number -1. Ciao. Gian Carlo macchi@scn.deReturn to Top
Richard ScottReturn to Topwrote: > I am a senior undergraduate student here in Hawaii majoring > in Mathematics. If I went on to a graduate school my interest > would be in studying sport (football of 2-3 codes in particular) > from a statistical viewpoint to predict team performance, player > statistics, rate performances, and provide other information. > I have seen some papers that have looked at this in some old > journals of the American Statistical Association. I have some > questions that hopefully some people can provide some insight > into or tips or pointers on where to go to find out. > My questions are :- > > 1) Is this a feasible area of research? I have been working on > it in a basic way given my own limited resources and time for > the past few years. Yes > 2) Following from 1) is that at all useful, employment-wise do > you think? Are professional teams or others interested in > this sort of information? I have had an article or two > published in fantasy football magazines, which is basically > all about player performance prediction, so a long-term study > such as is done in the baseball field would be interesting, I > think. Congratulations on publication!! The interest of professional teams is fairly limited. You might try surveying some teams to see what they are doing and what their interests are. > 3) What are the best programs? I have no idea. But you might see who is publishing these type of papers in Stat journals and Sport journals and ask them. > 4) What programs might have people interested in the above type > of research? Operations Research as well, perhaps? Other > areas? Good question to ask of people in the Sport Behavior research business. > 5) Anything else you might like to add to enlighten a newbie > would be great. Keep publishing!! It's good karma!! Dick
rtomes@kcbbs.gen.nz (Ray Tomes) wrote: >davis_d@spcunb.spc.edu (David K. Davis) wrote: >>Pi, I believe will be discovered by intelligent life where ever and whenever it arises. >No. Intelligent life will discover 6.283193... or 2pi. Looks like Ray considers the discovery of pi and 2*pi to be mutually exclusive...maybe he just doesn't qualify as intelligent life. ;-) JeffMo "A valid argument is not formed solely by ignorance." -JeffMo "A valid argument is not formed solely by assertion." -JeffMo Religion : Science :: Methamphetamine : Exercise For email replies, remove the "dipstick." from my eddress. It should be self-evident that I am not a dipstick. ;-)Return to Top
Gian Carlo Macchi wrote: > > In article <5bc75q$1kj@news.usit.net>, Heath David hart > heath@homemail.com says... > > >macchi@marina.scn.de (Gian Carlo Macchi) wrote: > > >>I've not followed this thread until now. Anyway, in your example, Roman > >>I always counts 1, independently of its position, and X always counts > >>10. > >>That is why this numbering system is not positional. > > >I think it could reasonably be argued that in 'VI' the symbol 'I' has > >a value of 1, but in 'IV' the symbol 'I' has a value of -1. > > Negative numbers do not apply to Roman numbering system. So the I in IV > can be seen as the number 1 that has to be subtracted to V; so we can say > that IV corresponds to 4, i.e. 5 - 1, where the minus is an operator > applied to the couple of numbers 5 and 1, not the sign of the number -1. According to Conway and Guy, the Romans didn't really use the positional subtraction - widespread use started in medieval times. -- D. mentock@mindspring.com http://www.mindspring.com/~mentock/index.htmReturn to Top
Etherman wrote: > > Recently I have been thinking a lot about how to find a curve that best > matches a given set of points. Today I got an idea. Why not try > to find the differential equation that best describes a set of points? > It's fairly trivial to find the best simple harmonic oscillator diff. This can be done and is a very useful technique for physical modelling. For systems in which the solution to the DEQ doesn't have an analytic form, one can still compute a numerical table of the solution, compute chi^2 from this, and apply a minimizing algorithm to solve it. Marcus Mendenhall Vanderbilt UniversityReturn to Top
On Tue, 14 Jan 1997 20:47:05 -0800, Rodney HunsickerReturn to Topwrote: >... God is known through faith, and faith is grown in love. >Love is the only "light" that can reveal the existance of God. But only if the "love" in question is on the "approved list", right? Gay and lesbian love is not on that list, is it, Rodney? Can you spell "HYPOCRISY", Rodney?
Richard Mathar (mathar@qtp.ufl.edu) wrote: : dasher@netcom.com (Anton Sherwood) wrote on Mon, 30 Dec 1996: : > Wanted: number of spheres that can pack around a sphere : > in n dimensions; I have for n up to 10 (2 6 12 24 40 72 : > 126 240 272 306), want up to 16. See "New Sphere Packings inDimensions 9-15" by J. Leech & N. Sloane, A.M.S. Bulletin, September 1970, pages 1006-1010.They show maximums: Dimension Spheres touched 9 306 10 500 11 576 12 840 13 1130 14 1582 15 2564 Of course higher values may have been discovered since. Brian CalvertReturn to Top
In article <5bhcu9$go3@sun001.spd.dsccc.com>, Mike McCartyReturn to Topwrote: > >You are confusing proper time and time as measured by an observer. The >collapse proceeds very speedily in proper time (i.e. time as actually >seen by the one falling into the black hole). You might investigate the >Kruskall coordinates for a black hole. This sounds like an improved modern version of the Zeno paradox about Achilles and the tortoise: In the original paradox Achilles cannot pass the tortoise because he first has to pass an infinite number of points, and this may be solved by noting that the length of time is still finite. In the new version, the black hole cannot form because it takes an infinite length of time, and this is solved by noting that this time is finite from another point of view. Greetings, Ørjan.
This should make it clear once and for all. ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Define a perfect continuous function as being a function f:[0,1]->R(the set of real numbers) ^ the compact[0,1] and for all x in [0,1] there is a sequence {x_n} which converges to x (but it is not constant (=x) starting from any n) such that f(x_n)=f(x) Prove: The sum of two perfect continuous functions is a perfect continuous function. ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ BobReturn to Top
Dave Seaman wrote: > > > I have read that the original purpose of BASIC was to teach beginning > programming students about concepts of assembly language, hence the > line numbers, the global namespace, and the lack of structured > programming concepts. > Are you sure? I don't see how the concepts of assembly language can ever be taught by teaching BASIC. Rather, I think BASIC was developed so that people did not have to learn the concepts of assembly language and still be able to program a computer by using an English-like language. Regards, Shyang HwangReturn to Top
"John P. Boatwright"Return to Topwrote: Bloatwad is in prime shape for his table dance routine. He will be leading a contingent of Whores For Christ at Easter. At a certain point in the Easter parade, Bloatwad and his mom will drop their robes and do their table dance routine to adoring fans (each other). I hope they arrest him again. Geo If atheism ever becomes a capital offense, then I want to be regarded as the Charles Manson of atheism. - Geo
In article <5bifum$lc8@rzsun02.rrz.uni-hamburg.de>, Hauke ReddmannReturn to Topwrote: >Does this experience sound familiar to you? > >So: Did you ever dreamt up some nobel-prize >worthy theory, just to realize after awakening >that it violates five conservation laws >and the data too? I have read and composed verse in dreams that simply didn't rhyme at all in real life. The meter always seems to work but the rhymes tend to be not even close. Nothing Nobel-worthy, however. While we're on the subject, I once collected a list of "You know you've been mathing too long when..." stories, many of which involved zany things that occurred to people in dreams (one fella was awakened by roomies when he was found on the floor, trying to find x). In any case, if you have any such stories (or even jokes, but make it clear if you're presenting a joke), email yours truly at caj@niu.edu. Thanks a googol. >Hauke Reddmann <:-EX8 ,oooooooo8 o ooooo@math.niu.edu -==- http://www.math.niu.edu/~caj/ o888' `88 ,888. 888 888 ,8'`88. 888 "Hey, you got your chocolate in my cod liver oil!" 888o. ,oo,8oooo88. 888 "Hey, you got your cod liver oil in my chocolate!" `888oooo88o88o o888o 888 -Common occurrence in the ___________________8o888'________________________days before peanut butter__
cyberman@zerocity.it (Cyberman) wrote: >Hello. I've a little problem: >I must invert this function: y = (x^2) + x for x >= 0 >Is there anybody that could help me? x^2 + x = x^2 + x + 1/4 - 1/4 = (x+ 1/2)^2 - 1/4 Complete the square. (x + 1/2)^2 - 1/4 = y (x + 1/2)^2 = (y + 1/4) x + 1/2 = +-SQRT(y + 1/4) You take it from there.Return to Top
In article <32D9DC04.C68@weirdness.com>, Keith PitcherReturn to Topwrites: >Hello, > recently my sister's math teacher asked a question, and did not accept >her >logical answer (He gave an "F" to the poor girl). I will be meeting with >the teacher this week to discuss this matter, and am seeking support to >show the teacher the error in his ways. > >His question for his standard 7th grade math class, in verbatim, was as >follows: > >Q) Take a square piece of paper. Fold it in half. Do it again. Repeat 25 >times. How many sheets thick is the final folded piece of paper. > > >My sister realized that this was a trick question, as she knew a piece >of paper can >not be folded that many times in half, and so far every question had >been based in reality. She came up with this description of her answer : > >A) Take a piece of paper and fold it in half. Now, to "Do it again" you >have to unfold the piece of paper and refold it again. (This would be >like closing your hand into a fist and being told to "Do it again." You >first have to open your hand) Repeat this 25 times. The final paper >would have just one fold, being two sheets thick. > > >The teacher gave this answer an "F", stating that the answer was wrong. >I disagree. >He asked a trick question, and he recieved a very logical answer. In >fact, the only answer that I can concieve that can actually work. She >has been able to answer the questions using first hand examples to >determine other problems. (Such as blocks of wood for area problems). >Further, if he wanted to reach an answer of 2^25 he should have phrased >the question much better, such as "Assuming you can fold a piece of >paper...." > >I am seeking opinions on his grade. Since you are asking for opinions, I will give you mine .... The question is ambiguously worded, as it is not clear what you are repeating 25 times (it asks for one fold, then a second, then to repeat - both folds, repeat one fold, repeat to a total of 25 times, etc.). However, I think that your sister's answer was probably not right. How many times was your sister's test paper folded? If you are going to interpret the question literally, then I would say that, unless the paper was folded at least twice, your sister got the question wrong. After all, the question does clearly say to "Take a square piece of paper. Fold it in half [etc. etc.]". I am guessing that the paper wasn't folded, in which case I would conclude that your sister realized that this was a hypothetical example and so should have answered it with a number like 2^25 (or 2^26, or even 2^50, depending on how one interprets the word "this" in the phrase "repeat this 25 times"). For further examples of the consequences of taking things literally, I refer you to the episode of "The Brady Bunch" where Greg gets hung-up on his parents "exact words" when issuing instructions, rather than the intent of the words (e.g., Greg drives a friend's car after being forbidden from driving because his dad told Greg he couldn't drive the family station wagon for a week). I am also a littled baffled as to why she got an "F" when she answered many other problems correctly. Did she get several other questions wrong? Is there more to the story than what you wrote? Regards, Mike Diebold ********************************************************************** Opinions are of the author, not DuPont **********************************************************************
The event horizon is not static: it expands to engulf the incoming matter. This happens in finite time even from the point of view of an external observer. See "Black Holes: The Membrane Paradigm" by Kip Thorne.Return to Top
In article <32DC6149.6C9C@fast.net>, Rodney HunsickerReturn to Topwrote: [snip snip snip, snippy snippy snip] >God made light. By it we see. Without it we cannot focus are attention >on externals. God made the world. We see it in light. >An infinite multitude of world exists in darkness and we see only what >the flashlight of our preception can capture momentarily. Math is a >vain attempt to place order on that which is already ordered. God is >said to be within. God cannot be seen in the light because he is not in >the darkness. God is known through faith, and faith is grown in love. >Love is the only "light" that can reveal the existance of God. God made vi. By it we edit. Without it we quote an entire article without removing irrelevant text. God made morons. We see them on USENET. An infinite multitude of people who can barely write articles about subjects they simply don't understand exists on USENET and we see only what the flashlight of our newsreaders can capture momentarily. These articles are a vain attempt to put down that which the authors know nothing about. God cannot be seen in the light of the newsreader because s/he is not on usenet, because s/he is not a one-taco-short-of-a-combination-plate moron. Furthermore, s/he clips quotes that aren't relevant to the discussion, and knows how to indent a damn paragraph. Oh, and s/he can spell big long hard words like "existence." .,-::::: :::. ....:::::: @niu.edu -- http://www.math.niu.edu/~caj/ ,;;;'````' ;;`;; ;;;;;;;;;```` [[[ ,[[ '[[, ''` `[[. "I'd like a large order of FiboNachos." $$$ c$$$cc$$$c ,,, `$$ "Okay sir, that'll cost as much as a `88bo,__,o, 888 888,888boood88 small order and a medium order combined." "YUMMMMMP"YMM ""` "MMMMMMMM" _____________________________________________
In article <5bhhau$edv@news.iastate.edu>, Alexander AbianReturn to Topwrote: > >Abian answers: > >Dear Mr.Kastanas, > > First of all thank you for your informative e-mail. You are welcome. > However, I still tend to believe that with very clever choices for > postes and extremely clever usage of dense subsets - the language > of Forcing can be avoided. > > I would like to see if you can consider proving the following two > statements in a straight forward way using suitable posets and > their dense subsets. > > Let M be Cohen's minimal model. Let us assume that we DO NOT > ^^^^^^^^^^^^^^^^^^^^^^^^^^^^ > KNOW THAT CH and Zorn's Lemma are valid in M. > ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ > > (1) Can you prove that some generic extension of M would > be a model for ZF+ CH ? > >(2) Can you prove that some generic extension of M would > be a model for ZF + Zorn's Lemma (preferably Zorn's > Lemma and not its equivalent AC)? I'm in favor of a "dense sets" view of forcing; e.g. forcing in arithmetic or analysis. Incomparable degrees (Kleene-Post) were really an early forcing result, and by using only certain dense sets one got recursiveness in 0-jump. In set theory, on the other hand, one typically has G meeting _all_ dense sets in M; one then argues that this dense set or that one is in fact in M. The language of forcing ("L.F.") provides a systematic, if not clever, way of doing so over a wide range. One cannot exactly "forget" the properties of the minimal model, since what happens in M[G] is very much affected by what is the case in the ground model. I would interpret this request as one to start with some M, countable transitive model of ZF, and if AC or (G)CH do not hold, produce a model where they do. (I don't quite get the point about Zorn. The proof of AC <=> Zorn (<=> Wellordering <=> ...) is straightforward, good for any model, and at worst one can just repeat it). Also, the 'test cases' do not _need_ a forcing extension; obviously it is enough to construct L (in M... getting (L)^M, = some L_a). But let us consider M[G] anyway. Well, the fact is: L.F., the language of forcing, is for one thing the way one _defines_ M[G]. Note that if M = an L_b, the minimal one or otherwise, then Cohen's L[b, G] definition is an equivalent road to M[G]; but not in general. The iterative buildup of M[G] is by L.F., not by constructibility! It's a Catch-22; in the cases for which we know how to avoid the L.F. definition, AC and CH hold to begin with! Finally, suppose the above is overcome. Say we have 2^w = k > w_1 in M. We can go about adding a function that collapses k "without L.F."; but can we actually control global stuff like how many reals are added overall? I suspect the nitty-gritty of doing so is tantamount to using L.F. ... even if we don't call it by that name. Ilias
geibel@cs.tu-berlin.de (Peter Geibel) writes: < I am looking for ... a good, exact and general maximum clique < algorithm. ... perhaps there is a general algorithm that works well < for "almost all" graphs or at least many graphs with a property that < is not too restrictive. My graphs tend to be rather large but are not < symmetrical or regular. They are not planar but are sparsely connected. If this sparseness holds not just for the whole graph but also for any subgraph, i.e. if there is a constant c such that any k-vertex subgraph has at most ck edges, then you can find the max clique in time something like O(2^{2c} n). Here's one easy algorithm (from my paper ChrEpp-TCS-91, for an earlier linear time algorithm see ChiNis-SJC-85, full references below): repeat until graph empty: find a minimum-degree vertex v check whether each large subset of neighbors is a clique delete v from the graph To make this linear time you need some simple data structures to find the min degree vertex and to test whether an edge exists in the graph Both can be done in constant time per operation (the main point of ChrEpp-TCS-91 is to address the edge existence test using a method based on similar ideas of ordering the vertices by degree). Probably the 2^{2c} (which is the number of subsets of neighbors) can be improved to a smaller exponential term by using a faster dense-graph clique algorithm (e.g. that of Rob-Algs-86) in the graph induced by the neighbors of v. Sorry, I have less info on your matching problem, although I do have some references on matching pairs of graphs in one of my bibliography files, http://www.ics.uci.edu/~eppstein/bibs/subiso.bib References: @article{ChiNis-SJC-85, title = {{Arboricity and subgraph listing algorithms}}, author = {N. Chiba and T. Nishizeki}, journal = {SIAM J. Computing}, volume = {14}, pages = {210--223}, year = {1985}} @article{ChrEpp-TCS-91, title = {{Planar orientations with low out-degree and compaction of adjacency matrices}}, author = {Marek Chrobak and David Eppstein}, journal = {Theoretical Computer Science}, volume = {86}, pages = {243--266}, year = {1991}} @article{Rob-Algs-86, title = {{Algorithms for maximum independent sets}}, author = {J. M. Robson}, journal = {J. Algorithms}, volume = {7}, pages = {425--440}, year = {1986}} -- David Eppstein UC Irvine Dept. of Information & Computer Science eppstein@ics.uci.edu http://www.ics.uci.edu/~eppstein/Return to Top
luke wrote: > how big would a black hole be? i don't know much about astrophysics, so > i > don't even know in what units the answer would be. how big would it be > compared to the earth or to the sun? when i say big i mean diameter or > circumference. The Schwarzschild radius R for a black hole of mass m is R = 2 G m/c^2, where G is the universal constant of gravitation and c is the speed of light in vacuum. The Schwarzschild radius for the Sun is about 3 km, whereas it is about 1 cm for the Earth. -- Erik Max Francis | max@alcyone.com Alcyone Systems | http://www.alcyone.com/max/ San Jose, California | 37 20 07 N 121 53 38 W &tSftDotIotE; | R^4: the 4th R is respect "You must surely know if man made heaven | Then man made hell"Return to Top
I've looked through the Griess and Schneider materials, and they look interesting. However, one thing that seemed to be lacking was discussion of how to read and write proofs in conventional mathematical English. Given that students will ultimately have to read and write proofs in this style, how do you motivate the transition from proofs in this very formalized style to proofs written in English? -- Brian Borchers borchers@nmt.edu Department of Mathematics http://www.nmt.edu/~borchers/ New Mexico Tech Phone: 505-835-5813 Socorro, NM 87801 FAX: 505-835-5366Return to Top
give a nigga yo adressReturn to Top
In <5bi86p$2kp@nntp1.u.washington.edu> hillman@math.washington.edu (Christopher Hillman) writes: > >In article <5bhpbg$hfq@dfw-ixnews9.ix.netcom.com>, >odessey2@ix.netcom.com (Allen Meisner) writes: > >|> Mr. Hillman, you explained in another post that mass and kinetic >|> energy both contribute to the mass-energy of a particle. > >Yes, the total energy (expanded in a power series in v) is > > m/Sqrt{1-v^2} ~ m + (1/2) m v^2 + (3/8) m v^4 + ... > >where the first term is the mass, the second term is the Newtonian >value for the kinetic energy, and the remaining terms may be considered >relativistic corrections to the kinetic energy (which are important only >for values of v close to 1). > >|> You stated in another post that the >|> velocity space of a body is a Lobachevsky geometry. > >Yes, The velocity space is space of forward pointing unit vectors, which >can act as tangent vectors to world lines; the spacelike components of such >vectors are interpreted as the components of the velocity and the timelike >component gives the time dilation rate at that event (for a clock carried >with the particle, relative to the rest frame). > >|> Mr. Archimedes >|> Plutonium has stated that the Lobachevsky geometry does not have a zero >|> reference point. > >In the same sense that ordinary euclidean space does not have any distinguished >points, he is correct. The euclidean plane, the ordinary sphere, the Lobachevsky >"hyperbolic" space (topologically a plane and thus often called "the hyperbolic >plane") and the velocity space of tachyons (topologically a cylinder) are all >surfaces of constant curvature and thus have no geometrically distinguished points. >Thus, the choice of an origin for any coordinate system is arbitrary. The >euclidean plane has constant curvature zero, and can be given the familiar >Cartesian coordinates. The remaining surfaces have constant nonzero curvature >and cannot be given a Cartesian coordinate system; in fact, the sphere cannot >be given ANY global coordinate system (i.e. one which avoids coordinate >singularities at all points) whereas the others can be given global, nicely >behaved conformal coordinate systems. One popular conformal system for >the Lobachevsky space was introduced by Poincare and maps this space onto >a disk of unit radius (with the geodesics represented as circular arcs >whose ends are orthogonal to the bounding circle). A good conformal >system for the tachyon velocity space is the exact analog of the Mercator >projection for the sphere (it represents lightlike geodesics as straight >line segments). > >|> Since a body with constant velocity has a non-zero slope in the Loba geometry, > >Unfortunately present technology does not support the drawing of a freehand >picture or two which would have greatly clarified my posting discussing >velocity spaces. In fact, a body with constant velocity (i.e. whose world >line has a constant unit tangent vector all along the world line) is >represented in the velocity space by a POINT. On the other hand, a body >with a curved world line experiences accelerations and such a world line >corresponds in the velocity space to a curve; in the case of constant >acceleration this curve is a geodesic (topologically a line) on the >Lobachevsky space. "Velocity space" is called that because its POINTS >correspond to possible values for the velocity associated with a >particular event on a given body's world line. > >What you wrote after the quoted remark seemed pretty far off the mark to >me--- possibly because of the misunderstanding just noted. > >Chris Hillman > > > Ok Mr. Hillman, what I would like to ask now is whether the topology of the velocity space is responsible for the inertial motion of a body in the same way that the topology of the gravitational field is responsible for the acceleration of a body. My ideas that you say are far off the mark arose because I was confused about how a static curvature in spacetime could cause the motions of bodies. Why does a curvature in space time constrain an object to move? Obviously you can not use gravity to explain gravity. This problem was worrying me and I am wondering if you can ease my mind. Also, if the topology of the velocity space is the cause of inertial motion, is time dilation the only explanation for the Lobachevsky curvature? I must admit that I can not see how this is so. Wouldn't time dilation give you the flat spacetime of SR and the Lorentz metric? It seems to me that only absolute time and length dilation can give the Lobachevsky metric. Regards, Edward MeisnerReturn to Top
Jeffrey Rubin wrote: > > David Ullrich (ullrich@math.okstate.edu) wrote: > <Return to Top> > > Thank you David. As in the past, you have come through for me with a > clear direct answer to my question. I really appreciate you volunteering > so much of your time to help people out on the net (sci.math in particular) > and I hope you will continue to do so. What a curious attitude ... -- David Ullrich ?his ?s ?avid ?llrich's ?ig ?ile (Someone undeleted it for me...)
Howard wrote: [...] > What does "physically impossible" mean in math? It means "a not true statement in a (fictitious) system called 'Physical Reality.'" Of course, fictitious is a bit strong; there's a readily available model. :) -- -- Eric Gindrup ! gindrup@okway.okstate.eduReturn to Top